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Olenka [21]
3 years ago
7

Can someone just talk to meeee

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

SURE I CAN!!!!!!!!!!!!!!!!!!

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1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,

A = L*H = 12*6 = 72 cm^2

3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).

Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2

4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.

Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
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What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?
natita [175]

Answer:

Remainder is 691.

Step-by-step explanation:

Given function is 10x^4-6x^3+5x^2-x+1.

Now we need to find remainder if we divide given function 10x^4-6x^3+5x^2-x+1 by (x-3)

(x-3) means plug x=3 into 10x^4-6x^3+5x^2-x+1 to find remainder.

10x^4-6x^3+5x^2-x+1

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Hence remainder is 691.

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3 years ago
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