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lana66690 [7]
3 years ago
5

What is the greatest common factor of 4k, 18k4, and 12?

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:  The greatest common factor is 2.

Step-by-step explanation:  We are given to find the greatest common factor of the following expressions:

E_1=4k,~~E_2=18k^4,~~E_3=12.

<u>Greatest Common Factor:</u>  The GCF of two or more numbers (expressions)  is the greatest factor that divides all the numbers or expressions.

We have

E_1=4k=2\times 2\times k,\\\\E_2=18k^4=2\times 3\times 3\times k\times k\times k\times k,\\\\E_3=12=2\times 2\times 3.

Therefore, the greatest common factor will be

G.C.F.=2.

Thus, the required greatest common factor is 2.

seraphim [82]3 years ago
4 0
Greatest common factor or GCF is the greatest factor that divides two numbers. So the get the greatest common factor of the 4k 18k and 12 you need to list the prime factors of each number then multiply both numbers have in common. So the greatest common factor of the numbers is 2 
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Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

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Required

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P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

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P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

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2 years ago
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postnew [5]
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hope this helped :)
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Step-by-step explanation:

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