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lana66690 [7]
3 years ago
5

What is the greatest common factor of 4k, 18k4, and 12?

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:  The greatest common factor is 2.

Step-by-step explanation:  We are given to find the greatest common factor of the following expressions:

E_1=4k,~~E_2=18k^4,~~E_3=12.

<u>Greatest Common Factor:</u>  The GCF of two or more numbers (expressions)  is the greatest factor that divides all the numbers or expressions.

We have

E_1=4k=2\times 2\times k,\\\\E_2=18k^4=2\times 3\times 3\times k\times k\times k\times k,\\\\E_3=12=2\times 2\times 3.

Therefore, the greatest common factor will be

G.C.F.=2.

Thus, the required greatest common factor is 2.

seraphim [82]3 years ago
4 0
Greatest common factor or GCF is the greatest factor that divides two numbers. So the get the greatest common factor of the 4k 18k and 12 you need to list the prime factors of each number then multiply both numbers have in common. So the greatest common factor of the numbers is 2 
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Answer:


Step-by-step explanation:

1. 3.8 x 10^5 + 5.5 x 10^5 = 930,000 or 9.3 x 10^5

You just have to solve the equation and shorten the answer. For number one the answer is 930,000, so you have to make it into a number with decimals since a scientific notation number can not be equal to 10 or be greater. So you have to round the number to 9.3 not 93. To "round" it to 9.3 you have to move the decimal at the end of 930,000 to be in between the numbers 9 and 3. How many times you move the decimal to the left or right, that is the exponent of 10. So for 930,000 you moved the decimal 5 times to the left so the exponent for 10 is positive 5.

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3 years ago
Select the equivalent expression (7^2 x 5^6)^4
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Answer:

<em>The answer is B.</em>

{( {7}^{2} . {5}^{6}) }^{4}  \\  =  {7}^{8} . {5}^{24}

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3 years ago
If 5x+5=50 <br> then solve for x
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2 years ago
Read 2 more answers
Factor this expression
Julli [10]

Answer:

6(6x^2-4x-3)

Step-by-step explanation:

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Will award a lot of points :)
WARRIOR [948]

Answer:

Step-by-step explanation:

Your final answer is the standard form of a parabola.  Since your equation has an x-squared term in it and not a y-squared term, your form will be

(x-h)^2=4p(y-k)

To get it into this form we will solve the quadratic for y and then set it equal to 0 so we can complete the square on it.  Solving for y then setting y equal to 0:

x^2-2x-23=8y so

\frac{1}{8}x^2-\frac{2}{8}x-\frac{23}{8}=0

We only need to complete the square on the x-terms, so we will move the constant back over to the other side of the equals sign:

\frac{1}{8}x^2-\frac{2}{8}x=\frac{23}{8}

The rule for completing the square is that the leading coefficient HAS to be a 1.  Ours is 1/8, so we have to factor it out.  When we do that we are left with:

\frac{1}{8}(x^2-2x)=\frac{23}{8}

To complete the square on the left, we take half the linear term, square it, and add it onto both sides.  Our linear term is 2 (the number stuck to the x-term).  Half of 2 is 1, and 1 squared is 1.  So we add it into the parenthesis on the left.  BUT we cannot discount the 1/8 sitting out front there.  It is a multiplier.  So what we actually added on the left is 1/8(1).  That looks like this:

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Now we will write the left side into its perfect square binomial (which was the whole reason for doing this!) and simplify the right at the same time:

\frac{1}{8}(x-1)^2=\frac{24}{8}

Now we will set the whole thing back to equal y:

\frac{1}{8}(x-1)^2-3=y

That's one form.  But you need it in vertex form, so we add 3 to both sides:

\frac{1}{8}(x-1)^2=y+3 and then multiply both sides by 8:

(x-1)^2=8(y+3)

If you need to break it down further to include what your p value is, then:

(x-1)^2=4(2)(y+3)

Either that one or the one right above it should work.

3 0
2 years ago
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