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KIM [24]
3 years ago
15

SOMEONE PLEASE ANSWER ASAP THIS FOR BRAINLIEST!!!!

Mathematics
1 answer:
kirill115 [55]3 years ago
3 0

wow the answer is not listed on option

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The ratio of the number of men to the number of women in a sports club is 5:2.
user100 [1]

Let the number of men and the number of women in the beginning be x and y

Now,\sf  \frac{x} {y} =\frac{5}{2} \\\\\sf=2x=5y \\\\\sf=x=\frac{5y}{2}

Now, In 2nd case,

No. Of men=x-63 and no. Of women =y-12

Now,the ratio becomes\frac{x-63}{y-12}=\frac{7}{4} \\\\\sf=4(x-63)=7(y-12) \\\\\sf=4x-252=7y-84 \\\\\sfPutting,\:x=\frac{5y}{2}\:in\: 4x-252=7y-84\:we\: get, \\\\\sf10y-252=7y-84 \\\\\sf=10y-7y=252-84 \\\\\sf=3y=168 \\\\\sf=y=56 \\\\\sf=\boxed{Y=56}

Now,we have, 2x=5y

Putting the value of Y=56 in 2x=5y,we get,

\sf 2x=5\:x\:56 \\\\\sfx=\frac{5\:x\:56}{2} \\\\\sfx=\frac{5\:x\: \cancel{56}\:\:28}{ \cancel{2}} \\\\\sf=x=5\: x\: 28 \\\\\sfx=140 \\\\\sf\boxed{x=140}

Hence, the number of men was 140 and the no. of women was 56

Hi...I am from India.. Where are you from?

8 0
3 years ago
Which ordered pair is a solution to the graphed inequality?
aleksandr82 [10.1K]

Given:

The graph of a system of inequalities.

To find:

The ordered pair which is a solution to the graphed inequality.

Solution:

The boundary lines are:

x-2y=4

2x-y=4

From the given graph it is clear that only point (3,1) lies in the shaded region.

Points (2,-1) and (4,0) lie on the boundary line x-2y=4 but the boundary line is dotted. It means the points on the line are not in the solution set.

point (0,-1) does not belong to the shaded region.

Therefore, the correct option is A.

8 0
3 years ago
What is g(5) for the sequence g={(6,3), (-4,2), (5,0)}
adelina 88 [10]
G(5) for the sequence g = <span>{(6,3), (-4,2), (5,0)} is 0</span>
7 0
3 years ago
What is the solution of x-3=12?
Snowcat [4.5K]

Answer:

The answer is 15

Step-by-step explanation:

15 - 3 = 12

4 0
3 years ago
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Simplify 21v ^-6 divided by (-7v^-6)
miskamm [114]
The answer is -3. I just did it on a calculator
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3 years ago
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