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olga nikolaevna [1]
3 years ago
6

HELP ASAP IM IN A TIMED TEST 8TH GRADE MATH ​

Mathematics
1 answer:
sattari [20]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Convert them all to the form y = mx + c

1)

4x + 3y = 15

3y = -4x + 15

y = -4/3 x + 5

2)

3x - 4y = -8

-4y = -3x - 8

4y = 3x + 8

y = 3/4x + 2

3)

y + 1 = 4/3(x - 6)

y + 1 = 4/3x - 8

y = 4/3x - 9

4)

y = 3/4x - 5

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Read 2 more answers
Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).
Romashka-Z-Leto [24]

The equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3) in slope intercept form is y = \frac{-1}{5}x + \frac{16}{5}

<h3><u>Solution:</u></h3>

Given that a line is parallel to line x + 5y = 10 and passes through the point (1, 3)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  -------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

Given equation of line is x + 5y = 10

5y = -x + 10\\\\y = \frac{-1}{5}x + \frac{10}{5}\\\\y = \frac{-1}{5}x + 2

On comparing the above equation of line with slope intercept form,

m = \frac{-1}{5}

We know that slopes of parallel lines are equal

So the slope of line parallel to given line is also m = \frac{-1}{5}

<em><u>Let us find the equation of line with slope m = -1/5 and passes through the point (1, 3)</u></em>

\text {substitute } m=\frac{-1}{5} \text { and }(x, y)=(1,3) \text { in eqn } 1

3 = \frac{-1}{5} \times 1 + c\\\\15 = -1 + 5c\\\\16 = 5c\\\\c = \frac{16}{5}

<em><u>Thus the required equation is:</u></em>

\text {substitute } m=\frac{-1}{5} \text { and } c=\frac{16}{5} \text { in eqn } 1

y = \frac{-1}{5}x + \frac{16}{5}

Thus the required equation of line is found

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3 years ago
Factorise p^2 + q^2 +5(p^2 + q^2)​
Vinvika [58]

Step-by-step explanation:

p² + q² + 5(p² + q²)

= 1(p² + q²) + 5(p² + q²)

= (1 + 5)(p² + q²)

= 6(p² + q²).

5 0
3 years ago
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