Question

How to find the area of composite polygon that have a base of 16 meters height of 18 meters and a height of 11 meters.

Answer 1

The area of the composite polygon is:

$\boxed{A_{T}=376 \ m^2}$

Explanation:

Hello! remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll choose the figure below in order to illustrate this problem. A composite polygon is a polygon that can be divided into two or more basic shapes. So here we have a composite polygon formed by a triangle and a rectangle. So:

$A_{total}=A_{T} \\ \\ A_{triangle}=A_{tr} \\ \\ A_{rectangulo}=A_{r} \\ \\ \\ A_{tr}=\frac{b\times h}{2} \\ \\ b:Base \ of \ the \ triangle \\ \\ h:height \ of \ the \ triangle \\ \\ \\ A_{r}=B\times H \\ \\ B:base \ of \ the \ rectangle \\ \\ H:height \ of \ the \ rectangle$

So the area of the composite figure is:

$A_{T}=\frac{16\times 11}{2} + 16\times 18 \\ \\ A_{T}=88+288 \\ \\ \boxed{A_{T}=376 \ m^2}$

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Dilation: brainly.com/question/10946046

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