Answer:Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Answer:
(y-p)/2
Step-by-step explanation:
take p to the left side. + p becomes - p. Now divide the whole thing by 2
Answer:
Here is how you do it step by step.
Step-by-step explanation:
Step 1: Simplify each side, if needed.
Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.
Step 3: Use Mult./Divide
Step 4: Check your answer.
I find this is the quickest and easiest way to approach linear equations.
Example 6: Solve for the variable.
<u>Hope this helps!</u>
Answer:
I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Step-by-step explanation:
Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:
8 x 0.95 + 4.5 x 0.05 = 7.825
8 x 0.94 + 4.5 x 0.06 = 7.79
0.94 x 28 = 26.32
26.4 x 8 + 1.6 x 4.5 = 218.4
218.4 / 28 = 7.8
Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the line y = - x
a point (x, y ) → (- y, - x ), thus
T(- 1, 3 ) → T'(- 3, 1 )
U(- 1, 10 ) → U'(- 10, 1 )
V(- 2, 4 ) → V'(- 4, 2 )
