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3 years ago

Find the angle measure of angle E in Triangle DEF if angle D is 34 degrees & angle E is 117 degrees.

Mathematics

1 answer:

Sliva [168]3 years ago

4 0

Answer:

Step-by-step explanation:

full angle of a triangle is 180 and 34+177=151 then you just do 180-151=29.

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What is the nth term?

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago

Using technology, determine the monthly payment on a 35 month loan of $28,000 at 8.1% compounded annually. Round you answer to t

sdas [7]

Present Value of an annuity is given by the formular
PV = P(1 - (1 + r)^-n)/r; where PV = $28,000, r = 0.081/12 = 0.00675, n = 35 and P is the periodic (monthly) payment.

P = PVr/(1 - (1 + r)^-n) = (28,000 x 0.00675)/(1 - (1 + 0.00675)^-35) = 189/0.2098 = 900.90

Therefore, the monthly payment is $900.90

7 0

3 years ago

How many multiples of 4 are there in {n; 37< n <1001}?

s2008m [1.1K]

Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
-40
-------
960

Dividing this by 4, we get 240. Adding 1, we get 241.

Finally, subtract 9 from 241: We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number?

5 0

3 years ago

Please help !! Picture provided !!!

adelina 88 [10]

Method One
Your calculator might be able to do this. Mine does it like this.
6
nCr
2
=
15

Method 2
You could simply set up 6C2

This gives you
$\frac{n!}{(n- r)! r!} = \frac{6!}{(6 - 2)!2!} = \frac{6!}{4! 2!} = \frac{6*5}{2*1} = 15$

Method Three
You only have to do this a couple of times to see how the cancellation works.

$\frac{6!}{4!2!} = \frac{6*5*\st{4*3*2*1}}{4*3*2*1 * 2*1}$
After all the cancellation takes place you have
6*5/2 = 15

7 0

3 years ago

If two distinct lines intersect, which is NOT necessarily true?

Inessa05 [86]

The lines are perpendicular.

8 0

3 years ago