Just put them in order from least to greatest and find out in between which number to put them . For example put 24 between 20 and 25.
Hope that helps .
By the Fundamental Theorem of Arithmetic, all number can be expressed as a product of prime numbers.
So naturally, lets divide 120 by an easy prime number.
We know that 120 is even, so lets try 2
120/2 = 60
lets keep dividing it by two until it becomes odd or prime
60/2 = 30
30/2 = 15
now lets see, what are some factors of 15?
Well the obvious ones are 3 and 5, both of which are prime. So now we can just count up how many times we divided it by 2
120/2 = 60
60/2 = 30
30/2 = 15
and 15 is just 3 x 5, so:
<span>
120=(<span>23</span>)×(3)×(5)</span>
or
<span><span>
120 = 2 × 2 × 2 × 3 × 5</span></span>
It's equal to 1.6x10^(-8)
Answer:
x = -16 or x = 6
Step-by-step explanation:
To find the roots of a polynomial function, set the polynomial equal to zero and solve for x.
x² + 10x - 96 = 0
We need to factor the left side. The left side is a quadratic polynomial whose first coefficient is 1. We need two numbers whose product is -96 and whose sum is 10. The numbers are 16 and -6.
(x + 16)(x - 6) = 0
If a product of two factors equals zero, then one factor or the other or both must equal zero.
x + 16 = 0 or x - 6 = 0
x = -16 or x = 6
