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3 years ago

Drop ur snaps (14/15 yrs)

Mathematics

2 answers:

timurjin [86]3 years ago

6 0

Answer:

audrey_111506

Step-by-step explanation:

lyudmila [28]3 years ago

3 0

That's on being a freshman

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A 4-column table with 4 rows. The first column has no label with entries C, D, E, total. The second column is labeled A with ent

Dahasolnce [82]

Answer:

0.69

Step-by-step explanation:

Just did it on edge and got it right

8 0

3 years ago

Read 2 more answers

Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is start fraction 1 over 6 e

Alona [7]

Answer: B. one-third

Step-by-step explanation:

Probability of picking a red marble, P(R) = 1/6

Probability of picking a yellow marble, P(Y) = 1/2

Therefore, the probability of picking a blue marble will be:

= 1 - (P(R) + P(Y))

= 1 - (1/6 + 1/2)

= 1 - (4/6).

= 1 - 2/3

= 1/3

The probability of picking a blue marble will be one third

8 0

3 years ago

What if the inverse of the function f(x)=4x+8

aliya0001 [1]

Here you go, hope I helped.

8 0

3 years ago

Read 2 more answers

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

3 years ago

The vertices of a triangle are as follows: (4,) (6,7) and (8,0) If you dilate the triangle by a scale factor of 3, what are the

Paraphin [41]

Given:

Consider the vertices of the triangle are (4,4) (6,7) and (8,0).

The triangle is dilated by a scale factor of 3.

To find:

The vertices of the new triangle after dilation.

Solution:

If a figure is dilated by scale factor k with origin as the center of dilation, then the rule of dilation is:

$(x,y)\to (kx,ky)$

The given figure is dilated by scale factor 3 with origin as the center of dilation, then the rule of dilation is:

$(x,y)\to (3x,3y)$

Let the vertices of the triangle are A(4,4), B(6,7) and C(8,0).

Using this rule of dilation, we get

$A(4,4)\to A'(3(4),3(4))$

$A(4,4)\to A'(12,12)$

Similarly,

$B(6,7)\to B'(3(6),3(7))$

$B(6,7)\to B'(18,21)$

And,

$C(8,0)\to C'(3(8),3(0))$

$C(8,0)\to C'(24,0)$

The vertices of the new triangle are (12,12), (18,21), (24,0).

Therefore, the correct option is 4.

7 0

3 years ago