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viva [34]
3 years ago
11

For her birthday, Kendra received a gift card in the mail from her grandparents. The gift card was worth $50. Kendra thought, si

nce she had just received other gifts for her birthday, she would wait a while to spend the gift card. Unfortunately, Kendra forgot all about the gift card, and the card loses $5 every month after its date of purchase if it has not been used. If Kendra forgot the card for three months, she lost $______.
A. 9
B. 10
C. 15
D. 12

i will give you brainiest and it has to be the right answer.
Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:15

Step-by-step explanation:

scoundrel [369]3 years ago
6 0

Answer:

$15

Step-by-step explanation:

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Slope 2 and passing through (10,17)
TiliK225 [7]

Answer:

y = 2x -3

Step-by-step explanation:

y = 2x + b

plug the point in to the formula and solve for b

17 = 2 x 10 + b

b = -3

Use this to write the formula y = mx + b

m is slope

6 0
3 years ago
What is the area of this figure (4,1)(2,2)(2,-2)(-4,-2)(-2,-5)(2,-5)
V125BC [204]

Answer:

The area of this figure is 45 square units.

8 0
3 years ago
The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot
Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

brainly.com/question/27270616

#SPJ4

       

       

4 0
2 years ago
Are these ratios equivalent?
vaieri [72.5K]

Answer:

Yes

Step-by-step explanation:

3 medium cars to 1 small car can be made into a fraction like this: \frac{3}{1} or \frac{1}{3}. But you must be consistent if the denominator represents medium cars or small cars.

For this, I'm just going to make medium cars the numerator.

18 medium cars to 6 cars can be made into a fraction like this : \frac{18}{6}.

When you divide both fractions in a calculator (or in your head), you will realize that they both are the same value (equivalent).

\frac{3}{1}=\frac{18}{6} = 3

\frac{1}{3} = \frac{6}{18} = .3333333

These ratios are equivalent.

4 0
3 years ago
12,430,000 in expanded form
Drupady [299]
10,000,000+2,000,000+400,000+30,000+0+0+0
8 0
4 years ago
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