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3 years ago

Pls help me out with these questions anwser 9 and 10 pls :) have a nice day there easy too!

Mathematics

2 answers:

Kruka [31]3 years ago

8 0

Where’s the photo ?

Schach [20]3 years ago

5 0

Answer:

9+10 is 21

Step-by-step explanation:

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Which equation can pair with X- y=-2 to create a consistent and dependent system?

OLEGan [10]

D is the correct answer to this question

5 0

3 years ago

In the figure, GK bisects FGH

bija089 [108]

Answer:

$w = 7$

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

$104 = 2*(7w + 3)$ (substitution)

Divide both sides by 2

$\frac{104}{2} = \frac{2*(7w + 3)}{2}$

$52 = 7w + 3$

Subtract 3 from each side

$52 - 3 = 7w + 3 - 3$

$49 = 7w$

Divide both sides by 7

$\frac{49}{7} = \frac{7w}{7}$

$7 = w$

$w = 7$

8 0

3 years ago

Today was my first day :p<br> Brainliest goes to whoever inserts the funniest picture :>

Artyom0805 [142]

this gotta be funny

5 0

3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago

Find the additive inverse of 7/10

11111nata11111 [884]

$\huge\fbox{Hi~there!}$

Remember, a number's additive inverse is simply its opposite.

Let's say we have a number a.

The opposite of a is -a, and the opposite of -a is a.

Thus, the additive inverse of

$\displaystyle\frac{7}{10}$ is

$\displaystyle-\frac{7}{10}$

Hope it helps.

~Just a felicitous girl

#HaveAnAmazingDay

Feel free to ask if you have any doubts.

$\bf{-MistySparkles^**^*$

5 0

3 years ago