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a_sh-v [17]
3 years ago
5

A constant function is a linear function. True False

Mathematics
1 answer:
Ksju [112]3 years ago
8 0
<span>Correct answer is A.

Anything with a constant gradient is a linear function.

y = c
y = 0×x + c
k = 0 - constant gradient</span>
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What is equivalent to ln(e^3)
malfutka [58]

Answer:

3

Step-by-step explanation:

The natural log is the inverse of the exponential (and vise versa), so ln(e^3) = 3.

(This is the also same as e^(ln3))

4 0
4 years ago
Read 2 more answers
Nalia worked 3.5 hours more than lisa together they worked a total of 18 hours lisa worked h hours
andre [41]

Answer:

7.25 and 10.75 Hours

Step-by-step explanation:

Total hours Nalia and Lisa worked = 18 Hours

Nalia worked 3.5 hours then Lisa which is h hours

⇒h + (h + 3.5) = 18

2h + 3.5 = 18\\2h = 18 - 3.5\\2h = 14.5\\h = \frac{14.5}{2} \\h = 7.25

Lisa has worked for 7.25 hours

Nalia has worked for = 7.25 + 3.5 = 10.75 hours

3 0
4 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
All my points to whoever can solve this
tankabanditka [31]

Answer:

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i

Step-by-step explanation:

5z^2−9z=−7z−5

We need to get all the terms on one side (set the right side equal to zero)

Add 7z to each side

5z^2−9z+7z=−7z+7z−5

5z^2−2z=−5

Add 5 to each side

5z^2−2z+5=−5 +5

5z^2−2z+5=0

This is in the form

az^2 +bz+c = 0 so we can use the quadratic formula

where a = 5   b = -2  and c = 5

-b± sqrt(b^2-4ac)

-------------------------

  2a

-(-2)± sqrt((-2)^2-4(5)5)

-------------------------

  2(5)

2± sqrt(4-100)

-------------------------

10


2± sqrt(-96)

-------------------------

10

2± sqrt(16)sqrt(-1) sqrt(6)

-------------------------

10

2± 4i sqrt(6)

-------------------------

10

1/5 ± 2/5 i sqrt(6)

Splitting the ±

1/5 + 2/5 i sqrt(6) = .2 + .98i

1/5 - 2/5 i sqrt(6) = .2 - .98i


3 0
3 years ago
Please help! I don't know this question.
Dimas [21]

Answer:

B. 14/15

Step-by-step explanation:

I hope this helps.

5 0
3 years ago
Read 2 more answers
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