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2 years ago

find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0

Mathematics

1 answer:

Vlad1618 [11]2 years ago

8 0

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

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3 years ago

I need help with 4 and 5

krok68 [10]

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area of figure = bh = 8x10 = 80
same as a trapezoid have base 6 and 14 and height 8
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a trapezoid with bases of 6 mm and 14 mm and a height of 8 mm

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3 years ago

find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0​

find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0