find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

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una escalera de 12ft de longitud esta apoyada contra una pared, de modo que su base se encuentra a 4 ft de la pared a nivel del

Marrrta [24]

Answer:

Step-by-step explanation:

Altura = 11.312 pies

i) La escalera que descansa contra la pared formará un triángulo en ángulo recto.

ii) la escalera formará la hipotenusa del triángulo rectángulo dado por h = 12 pies.

iii) La base está dada por 4 pies.

iv) de la fórmula del triángulo en ángulo recto.

base = $altura = \sqrt{hipotenusa^{2}\hspace{0.15cm}- \hspace{0.15cm} base^{2} } = \sqrt{12^{2}\hspace{0.15cm} - \hspace{0.15cm}4^{2} } = \sqrt{144\hspace{0.15cm} - \hspace{0.15cm}16} = \sqrt{128} = \hspace{0.15cm}8\sqrt{2} = 8\times1.414 = 11.312 pies$