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DENIUS [597]
2 years ago
7

find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0​

Mathematics
1 answer:
Vlad1618 [11]2 years ago
8 0

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

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2 years ago
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Answer:

23

Step-by-step explanation:

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2 years ago
Select the two statements that are true about the equation −10=60(−40)
Aleksandr-060686 [28]

Answer:

The slope of the line is 60  

One point on the line is (40, 10)  

Step-by-step explanation:

The missing choices are :

1) The slope of the line is 10  

2)One point on the line is (40, 10)  

3)The slope of the line is 60  

4)One point on the line is (10, 60)

Given the equation y−10=60(x−40),  applying distributive property we get:

y−10=60x - 60*40

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The slope is the number that multiplies x, that is, 60.

To check if the point (40, 10) belongs to the equation, replace the values x = 40 and y = 10 in the equation, as follows:

(10)−10=60((40)−40)

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(60)−10=60((10)−40)

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2 years ago
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Find the 52nd term of the following arithmetic sequence.<br> 17, 22, 27, 32, ...
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Answer:

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Step-by-step explanation:

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