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tino4ka555 [31]
3 years ago
6

Maggie has 16 pieces of tape, each piece of tape is 3/8th of an inch long. How much tape did Maggie use

Mathematics
2 answers:
DochEvi [55]3 years ago
8 0
I think the answer should be 6
expeople1 [14]3 years ago
7 0
16*(3/8)= 6 inches
the answer is 6 inches of tape
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Find the derivative of y= 1 / x​
givi [52]

Answer:

dy/dx = -1/x^{2}

Step-by-step explanation:

y = 1/x

dy/dx = d/dx(1/x)

=> dy/dx = d/dx(x^{-1})

=> dy/dx = -x^{-2}

=> dy/dx = -1/x^{2}

6 0
3 years ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
a copy shot prints 5,493 pages they use the pages to make 68 same size booklets about how many pages are in each booklet
Aliun [14]

Answer:

80 pages

Step-by-step explanation:

Given:

Number of pages printed = 5493

Number of booklets made = 68

Let each booklet use 'x' pages.

So, pages used by 68 booklets is given by unitary method and is equal to:

=68\times x\\=68x

Now, total number of pages are 5493.

Therefore, the pages used by the 68 booklets should be less than or equal to the total number of pages available. So,

68x=5493\\\textrm{Dividing both sides by 68,we get:}\\x=\frac{5493}{68}=80.8\approx 80(\textrm{As number of pages can't be in decimal})

Therefore, the number of pages in each booklet is 80.

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What's the point of brainliest .
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What are the possible values of x in -11x^2 + 2x = 10?
vlabodo [156]
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x = <u>-2 +/- √(-436)
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</u>x = <u>-2 +/- 2i√(109)
</u>              -22
x = <u>-2 + 2i√(109</u>)        x = <u>-2 - 2i√(109)</u>
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x = ¹/₁₁ - ¹/₁₁i√(109)    x = ¹/₁₁ + ¹/₁₁i√(109)
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8 0
3 years ago
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