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algol13
3 years ago
10

Does anyone know how to solve this? I don't even know how to start it ;-; please help, thanks

Mathematics
1 answer:
Maru [420]3 years ago
8 0
These shapes are geometric, which means they're equal. XW would be the same as XY, which is 18. The same goes towards WZ. WZ = ZY, so it'll be 29. Remember, since it's geometric, each side has to equal each other
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Simplify the expression. 8(s-1)
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Read 2 more answers
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Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

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  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

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  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
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3 years ago
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(1/5)/(5)=(1/5)(1/5)=1/25 of a pack of seeds will be planted in each pot

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