Let the number of blue marbles be x
number of yellow marbles = x/3
number of green = x- 90
ATQ
x + x/3 + x - 90 = 694
2x + x/3 = 784
(6x + x)/3 = 784
7x/3 = 784
x = 784 x 3/7
x = 112 x 3
x = 336
number of blue marbles = 336
Step-by-step explanation:
3(x+3)=12
3x+9=12
3x=12-9
3x=3
x=1
I’m pretty sure it’s b because they are camouflaged
Answer:
AC = 52
Step-by-step explanation:
Add the segment lengths together.
AB + BC = AC
22 + 30 = 52
Building time :
4c + 6a < = 120
testing time :
4c + 4a < = 100
20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)
4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)
ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
