I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
1. 0.7(29.95)
2. 1.04(284.99)
3. 49(0.75)(1.06)
4. 35+ 0.80m
5. 4500 (1.12)
Hope this helps!
1) This is not an arithmetic sequence because it has n².
2) To find 5 first terms of this sequence, you can simply substitute n with 1,2,3,4, and 5, and calculate values of a(1),a(2), a(3), a(4) and a(5).
a(n) = 3n²- 1
n=1 a=3*1² - 1 = 3-1=2
n=2 a=3*2² - 1 = 11
n=3 a=3*3² - 1 =26
n=4 a=3*4² - 1 = 47
n=5 a=3*5² -1 = 74
2,11,26,47,74
Answer C. 2,11,26,47,74.
Answer:
h ≈ 13.4
Step-by-step explanation:
Since the triangle is right we can use the sine ratio to find h
sin48° = 
= 
Multiply both sides by 18
18 × sin48° = h
⇒ h = 13.4 cm ( to 1 dec. place )
They are periodic functions with a period of 2π. The domain of each function is (−∞,∞) and the range is [−1,1]
