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SVEN [57.7K]
2 years ago
15

Train A and train B leave the station at 2 pm. The graph below shows the distance covered by the two trains. Compare the two spe

eds of the two trains. Show your work !

Mathematics
1 answer:
jarptica [38.1K]2 years ago
7 0

Both trains travel for 7 time units.

Train A travels 385 distance units, so its speed is

\dfrac{385}{7}=55

Train B travels 577.5 distance units, so its speed is

\dfrac{577.5}{7}=82.5

Note that the units are not specified, but considering that we're talking about trains, the graph is likely to be showing distance in km (or miles) and time in hours.

Also, the distance traveled by train B is not perfectly aligned with the grid, so I assumed that it was the average between the two ticks of 550 and 605.

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Answer:

Solid 1:

T.A. = 2(wl + hl + hw)

T.A. = 2(2 * 8 + 4 * 8 + 4 * 2)

T.A. = 2(16 + 32 + 8)

T.A. = 32 + 64 + 16

T.A. = 96 + 16

T.A. = 112m^2

V = w * h * l

V = 2 * 4 * 8

V = 8 * 8

V = 64m^3

M = 0.003 * 64

M = $0.19

Solid 2:

T.A. = l sqr(l^2 + 4 * h^2) + l^2

T.A. = 6 sqr(6^2 + 4 * 5^2) + 6^2

T.A. = 106m^2

V = 1/3 * b * h

V = 1/3 * 36 * 5

V = 12 * 5

V = 60m^3

M = 0.003 * 60

M = $0.18

Solid 3:

T.A. = (2 * pi * r^2) + (2 * pi * r * h)

T.A. = (2 * pi * 2.5^2) + (2 * pi * 2.5 * 3.5)

T.A. = (2 * pi * 6.25) + (2 * pi * 2.5 * 3.5)

T.A. = 39.27 + 54.98

T.A. = 94.25m^2

V = pi * r^2 * h

V = pi * 2.5^2 * 3.5

V = pi * 6.25 * 3.5

V = pi * 21.88

V = 68.72m^3

M = 0.003 * 68.72

M = $0.21

Solid 4:

T.A. = pi * r^2 + pi * r * sqr(r^2 + h^2)

T.A. = pi * 4^2 + pi * 4 * sqr(4^2 + 6^2)

T.A. = pi * 16 + pi * 4 * sqr(16 + 36)

T.A. = 50.26 + 12.56 * sqr(52)

T.A. = 62.82 * sqr(52)

T.A. = 140.9m^2

V = 1/3 * pi * r^2 * h

V = 1/3 * pi * 4^2 * 6

V = 1/3 * pi * 16 * 6

V = 1/3 * pi * 96

V= pi * 32

V = 100.5m^3

M = 0.003 * 100.5

M = $0.30

Solid 5:

T.A. = 4 * pi * r^2

T.A. = 4 * pi * 2.6^2

T.A. = 4 * pi * 6.76

T.A. = pi * 27.04

T.A. = 84.95m^2

V = 4/3 * pi * r^3

V = 4/3 * pi * 2.6^3

V = 4/3 * pi * 17.576

V = pi * 23.434

V = 73.62m^3

M = 0.003 * 73.62

M = $0.22

Write a paragraph that answers the following questions:

● Do all of the solids hold between 60 and 70 cubic inches?

● Which solid is the most cost efficient (the packaging with the smallest materials cost that holds between 60 and 70 cubic inches)?

● Would the Ark be most cost efficient solid for packaging? Why or why not?

● Which solid would you recommend using? Why?

● Why do you think that God was very specific in the measurements that He gave Noah for the Ark? Be sure to use some of your findings from this project to support your answer.

Of the five shapes, only the rectangular prism, the square pyramid, and the cylinder held between 60 and 70 cubic inches. The square pyramid was the most cost efficient, holding a price of $0.18. A rectangular prism would not be the most efficient shape cost wise, however it would be sufficient to hold the materials. I think I would recommend the rectangular prism for this project, because it is the second most cost efficient and holds a greater volume for use. I think God gave Moses the exact plans needed to perfectly fit all his animals. I think he wanted to prove to Moses his power and knowledge by providing the exact amount needed. In this project I took the measurements and I used them to discover which was best suited to serve the purpose needed, but God already knew and used it as a lesson in faith for Moses.

Step-by-step explanation:

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When Hiroto is writing, there is 0.920.920, point, 92 probability that there will be no spelling mistakes on a page. One day, Hi
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Complete question :

When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an essay that is 11 pages long.

Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?

Answer:

0.60

Step-by-step explanation:

The question meets the requirement for a binomial probability distribution :

Recall:

P(x = x) = nCx * p^x * q^(n-x)

Given :

Probability of making a spelling mistake = 1 - p(not making) = 1 - 0.92 = 0.08

Hence,

p = 0.08 ; q = 0.92

n = 11

P(x ≥ 1) = 1 - p(x = 0)

P(x = 0) = 11C0 * 0.08^0 * 0.92^11

P(x = 0) = 1 * 1 * 0.3996373778857415671808

P(x = 0) = 0.399

P(x ≥ 1) = 1 - p(x = 0)

P(x ≥ 1) = 1 - 0.399

P(x ≥ 1) = 0.601

P(x ≥ 1) = 0.60

3 0
2 years ago
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