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SVEN [57.7K]
3 years ago
15

Train A and train B leave the station at 2 pm. The graph below shows the distance covered by the two trains. Compare the two spe

eds of the two trains. Show your work !

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0

Both trains travel for 7 time units.

Train A travels 385 distance units, so its speed is

\dfrac{385}{7}=55

Train B travels 577.5 distance units, so its speed is

\dfrac{577.5}{7}=82.5

Note that the units are not specified, but considering that we're talking about trains, the graph is likely to be showing distance in km (or miles) and time in hours.

Also, the distance traveled by train B is not perfectly aligned with the grid, so I assumed that it was the average between the two ticks of 550 and 605.

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About 1.15 million people live in a circular region with a population density of about 18,075 people per square kilometer. Find
Tanzania [10]

Step 1

<u>Find the total area</u>

Total area=(1,150,000/18,075)=63.62 square kilometer

The area of a circle is equal to

A=\pi * r^{2} \\ 63.62= \pi * r^{2}\\r=\sqrt{(63.62/\pi)} \\r=4.5\ km

therefore

the answer is

4.5\ km

7 0
3 years ago
32 percent of the customers of a fast food chain order the Whopper, French fries and a drink. A random sample of 10 cash registe
weqwewe [10]

Answer: 0.0023

Step-by-step explanation:

Let X be the binomial variable that represents the number of receipts will show that the above three food items were ordered.

probability of success p = 32% = 0.32

Sample size : n= 10

Binomial probability function :

P(X=x)= \ ^nC_xp^x(1-p)^{n-x}

Now, the probability that eight receipts will show that the above three food items were ordered :

P(X=8)=\ ^{10}C_8(0.32)^8(1-0.32)^2\\\\=\dfrac{10!}{8!2!}(0.32)^8(0.68)^2\\\\=5\times9(0.0000508414176684)\\\\=0.00228786379508\approx0.0023

hence, the required probability = 0.0023

8 0
3 years ago
7/8 is 70% of what number?
tino4ka555 [31]
1.25 or 1 1/4 however you want to look at it
3 0
3 years ago
A rectangle has a width of 2cm and a perimeter of 25cm. Find the length and the area .
Gwar [14]

2w + 2l = 25

2 * 2 + 2l = 25

<em><u>Simplfiy.</u></em>

4 + 2l = 25

<em><u>Subtract 4 from both sides.</u></em>

2l = 21

<em><u>Divide both sides by 2.</u></em>

l = 10.5

Now that we have the value of l, we can find the area.

A = lw

A = 10.5 * 2

A = 21.

The length is 10.5cm.

The area of the rectangle is 21cm^2

5 0
3 years ago
Easy I am just not sure on how to solve it please give answer and how I would solve it
Elina [12.6K]

You want to compare the square root of 55 using "mental math". Start off by choosing two perfect squares that you can think of that are close to 55.

If you don't know perfect squares then start with the number 2 and multiply it by itself. 2 times 2 equals 4, so 4 is a perfect square.

Take the number 3, multiply it by itself, and so on. Do this for all the numbers until you find two perfect squares that are close to 55.

The two perfect squares closest to 55 are the square roots of 49 and 64. Find the square root of these numbers.

√49 = 7

√64 = 8

Calculate how far 55 is from 49 and 64. 55 is 6 digits away from 49 and 9 digits away from 64.

This means the square root of 55 will be closer to the square root of 49; 7. Since we know that it will be closer to 7, you can put the less than sign for your answer.

√55 < 7.7

(The actual square root of 55 is ~7.4, so we were correct in determining the answer without using a calculator!)

6 0
3 years ago
Read 2 more answers
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