Ask question

Ask question

All categories

3 years ago

12

A banner in the shape of a parallelogram has an area of 30 square feet. The height of the banner is 1/5 feet. What is the length

of the banner, in feet?

1 answer:

Vsevolod [243]3 years ago

5 0

Answer:

Q: 1 5 4 4 - 1 5 4 - 5 2 2 2 - 5 - - Find the size of the matrix - 2 1 4 -4 3 2 - 2 4 2,.

Step-by-step explanation:

You might be interested in

Question 9 (0.5 points)

exis [7]

The correct answer is C. 2,400

Explanation- I’m a freshman trust me I know!

6 0

3 years ago

3x - 6 + z (if x =9) (if z = 1 )

solmaris [256]

Answer:

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear!</u></em>

8 0

3 years ago

Read 2 more answers

A composite figure is comprised of a square and 4 semicircles. How can you decompose the composite figure to determine its area?

tangare [24]

Answer:

As a square and four semi circles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The the length of a rectangle is 9 centimeters less than four timesfour times its width. its area is 28 square centimeters. find

wel

Let w = width

then

5w-3 = length

w(5w-3) = 14

5w^2-3w = 14

5w^2-3w-14=0

(5w+7)(w-2) = 0

w = {-7/5, 2}

throw out the negative solution leaving

w = 2 centimeters

length:

5w-3 =5(2)-3 =10-3 = 7 centimeters

4 0

3 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago