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Amanda [17]
3 years ago
6

9^a-5 = 12 pls answer

Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer:

a=1.29 approx

Step-by-step explanation:

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Express the equation in the slope y-intercept form: y = mx + b. 2x−3y+1 = 0
horrorfan [7]

Answer:

y = 2/3x+1/3

Step-by-step explanation:

2x−3y+1 = 0

Solve for y

Add 3y to each side

2x−3y+1 +3y= 0+3y

2x +1 = 3y

Divide by 3

2/3 x + 1/3 =3y/3

2/3x +1/3 = y

The slope is 2/3 and the y intercept is 1/3

y = 2/3x+1/3

5 0
3 years ago
If you add the lengths of the focal radii of an ellipse, what other value will you produce?
ss7ja [257]

Equation of an ellipse

→having center (0,0) , vertex ((\pm a ,0) and covertex (\pm b ,0) and focus (\pm c ,0) is given by:

\frac{x^2}{a^2} + \frac{y^2}{b^2}=1

As definition of an ellipse is that locus of all the points in a plane such that it's  distance from two fixed points called focii  remains constant.

Consider two points (a,0) and (-a,0) on Horizontal axis of an ellipse:

Distance from (a,0) to (c,0) is = a-c = F_{1}

Distance from (-a,0) to (c,0) is = a + c = F_{2}

F_{1} + F_{2} = a -c + a +c

          = a + a

        = 2  a  →(Option A )


8 0
3 years ago
Read 2 more answers
12. Sean lives 2.25 miles<br> from school. Write this<br> distance as a fraction in simplest form.
mars1129 [50]
It would be 2 1/4 because .25 in fraction form is 1/4 because it is a quarter and then 2
4 0
3 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
There are 257 people at a dance performance. Orchestra seats cost $12 and balcony seats cost $8. The total receipts were $2,716.
solniwko [45]

x = # of balcony seats

y = # of orchestra seats

We have to create a system of equations to solve this problem

x + y = 256

$8x + $12y = $2,716

We will solve this system of equations by elimination.

Multiply the first equation by -8

-8x - 8y = -2048

8x + 12y = 2716

Let's add the equations together

0 + 4y = 668

Simplify the left side

4y = 668

Divide both sides by 4

y = 167

We can subtract 167 from 257 to get the number of balcony seats.

257 - 167 = 90 balcony seats

There are 167 orchestra seats and 90 balcony seats

5 0
3 years ago
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