(g*f)(0)= (x^3)*(2x+6)
(g*f)(0)= (0^3)*(2(0)+6)
(g*f)(0)= (0)*(0+6)
(g*f)(0)= (0)*(6)
(g*f)(0)= 0
The answer is C, because to find IQR you have to find the difference (subtract) of the first and third quartile
Answer:
37°
Step-by-step explanation:
∠ECF= ∠ACG
∠ACG= 90° - ∠GAC= 90° - 53°= 37°
At a constant speed Alan is traveling 7.27 repeating.
Answer:
Step-by-step explanation:
GH : √(8-4)^2 + (2-5)^2 = √16+9 = √25 = 5
HI : √(-6-2)^2 + (2-8)^2 = √64+36 = √100 = 10
IJ : √(-2-2)^2 + (-3+6)^2 = √16 + 9 = √25 = 5
JH : √(-2-4)^2 + (-3-5)^2 = √36 + 64 = √100 = 10
Slope of the line that contains GH
(2-5)/(8-4) = -3/4
Slope of the line that contains HI
(-6-2) / (2-8) = 8/6 = 4/3
I calculated the distance between points. Thanks to that I noticed that the opposite sides are congruent, so the quadrilateral can be a rectangle or a parallelogram. So I found the slope of the lines that contain two consecutive sides and I discovered that are perpendicular. So the quadrilateral is a rectangle because its angles are all of 90 degrees
