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lutik1710 [3]
3 years ago
8

Whst is 900 plus 59 please i need help i give u good points

Mathematics
2 answers:
Ivahew [28]3 years ago
6 0

Answer

900 + 59 = 959

MArishka [77]3 years ago
3 0

Answer:

959

Step-by-step explanation:

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Help me out please.i will give brainly
tankabanditka [31]

Answer:

Hello! answer: 17

Step-by-step explanation:

Assuming this is the Pythagorean theorem our formula would be

a^2 + b^2 = c^2

meaning both of those sides multiplied by themselves added together will equal a number which is the result of c multiplied byitself sorry it sounds confused but...

15 × 15 = 225 8 × 8 = 64 225 + 64 = 289

the square root or the (number multiplied byitself that equals 289) is 17 because

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0 As shown in the diagram below, M, R, and T are
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Answer:

The answer to your question is A.35

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The normal price of a pair of sneakers is $200. This week the pair of sneakers were on sale for only $150. By what percent did t
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25%

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Jane travels 7/8 distance to school by car, and walks the rest of the way. If she walks about 440 yd, what is the distance in mi
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7 0
3 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

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