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Snowcat [4.5K]
3 years ago
6

What is meant by byte in computer terminology​

Computers and Technology
2 answers:
dsp733 years ago
7 0

Answer:

Byte, the basic unit of information in computer storage and processing. A byte consists of 8 adjacent binary digits (bits), each of which consists of a 0 or 1. The string of bits making up a byte is processed as a unit by a computer; bytes are the smallest operable units of storage in computer technology.

Explanation:

Can I be brainliest? TYSMMMMMM      

lions [1.4K]3 years ago
5 0
A byte is a group of binary digits or bits (usually eight) operated on as a unit. It is considered as a unit of memory size.
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As the team leader, John ensures that all his teammates are clear in the team goals they need to achieve. He demonstrates the qu
zimovet [89]

Delegation ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

7 0
3 years ago
Read 2 more answers
Write a function "hailstone"that takes an int "n2"and prints the hailstone sequence. Hailstone Numbers:This sequence takes the n
givi [52]

Answer:

Here is the C program    

#include<iostream>  //for input output functions

using namespace std;   //to identify objects like cin cout

int Hailstone(int n2);   //function declaration of function Hailstone

int main()  {  // start of main() function body

int num;   // stores number entered by user

cout<<"Enter a number: ";  // prompts user to enter a number

cin>>num;   // reads the input number

while(num!=1) {  // loop continues until the value of num becomes 1

 num = Hailstone(num);  // calls hailstone method and passes num to it

cout<<num<<"\n";  }   }  // prints the hailstone sequence

int Hailstone(int n2)  {  //function takes int n2 and prints hailstone sequence

if(n2 % 2 == 0) {  // if the number is even

return n2 /=2;  }  // divide the n2 by 2 if n2 value is even

else {  // if n2 is odd

return n2 = (3 * n2) + 1;  }  }  // multiply n2 by 3 and  add 1 if n2 is odd

 

Explanation:

The function Hailstone() takes as parameter an integer which is int type and is named is n2. This function prints the hailstone sequence. The function has an if statement that checks if the number n2 input by the user is even or odd. If the value of n2 is even which is found out by taking modulus of n2 by 2 and if the result is 0 this means that n2 is completely divisible by 2 and n2 is an even number. So if this condition evaluates to true then n2 is divided by 2. If the condition evaluates to false and the value of n2 is odd then n2 is multiplied by 3 and 1 is added.

In the main() function the user is prompted to enter a number and the  Hailstone() function is called which keeps repeating until the value of n2 reaches 1.

4 0
3 years ago
You are the administrator for a small network. You have approximately 50 users who are served by a single Windows server. You ar
Paladinen [302]

Answer:

Rename the existing account, and change the name fields to match the new employee.

Explanation:

As you appoint new employer that need all the access to everything that the previous user had, including the documents files held in the Home Folder.

So, As an administrative of the network, you should Rename the existing account, and change the name fields to match the new employee.

4 0
3 years ago
Write a program TwoSmallest.java that takes a set of double command-line arguments and prints the smallest and second-smallest n
aliina [53]

Answer:

The following code is written in java programming language:

public class TwoSmallest {   //define class

   public static void main(String[] args) {     // define main function

       if (args.length < 2) {     //set the if condition

           System.out.println("Enter double values as command line arguments");

       } else {

           double minimum1 = Double.parseDouble(args[0]), minimum2 = Double.parseDouble(args[1]), n;

           if (minimum1 > minimum2) {    //set the if condition

               double temp = minimum1;

               minimum1 = minimum2;

               minimum2 = temp;

           }

           for (int i = 2; i < args.length; i++) {      //set the for loop

               n = Double.parseDouble(args[i]);

               if (n < minimum1) {

                   minimum2 = minimum1;

                   minimum1 = n;

               } else if (n < minimum2) {

                   minimum2 = n;

               }

           }

           System.out.println(minimum1);

           System.out.println(minimum2);

       }

   }

}

Explanation:

Here, we define a class "TwoSmallest" with public modifier.

Then, we define the main method.

Then, we set if condition and pass condition "args.length < 2".

Then we take three double type variable "minimum1", "minimum2" and "n".

Then, we set the if condition and pass condition if "minimum1 > minimum2", then set double type "temp" variable and swap between temp, minimum1 and minimum2.

Then, we set the for loop which is start from 2 and stops at "args.length"

Then, we set if condition and then we set its else part, after that we print the value of minimum1 and minimum2.

7 0
4 years ago
I need help here thanks forever who helps
lubasha [3.4K]

Answer:

the horse, the man, and the cactus

Explanation:

The horse is running

The man got slung off the horse, so its in motion

The cactus is flying everywhere from the horse.

3 0
2 years ago
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