Answer: ask google and search quizlet by it , it will show you
Explanation:
A speaker sometimes is not able to capture the intended details since it is affected by homophones.
In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
<h3>What are BPDU used for?</h3>
A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often transmitted in a local area network to be able to know or find loops in that given network topologies.
Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
See full question below
. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?
a. BPDU filter
b. BPDU guard
c. root guard
d. BPDU drop
Learn more about ports from
brainly.com/question/10097616
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If you are using CSS
:
table {
border-collapse: collapse;
border: 5px solid black;
width: 100%;
}
td {
width: 50%;
height: 2em;
border: 1px solid #ccc;
}
HTML
<table>
<tbody>
<tr><td></td><td></td></tr>
<tr><td></td><td></td></tr>
<tr><td></td><td></td></tr>
</tbody>
</table>
for HTML:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Sample table</title>
<style>
table {
border-collapse: collapse;
border: 5px solid black;
width: 100%;
}
td {
width: 50%;
height: 2em;
border: 1px solid #ccc;
}
</style>
</head>
<body>
<table>
<tbody>
<tr><td></td><td></td></tr>
<tr><td></td><td></td></tr>
<tr><td></td><td></td></tr>
</tbody>
</table>
</body>
</html>
Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.
Answer:
import math
def rectangle(perimeter, area):
l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4
l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4
l2_1 = area/l1_1
l2_2 = area/l1_2
print(l1_1,l2_1)
print(l1_2,l2_2)
if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:
return(int(max(l1_1,l2_1)))
elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:
return(int(max(l1_2,l2_2)))
else:
return(None)
Explanation:
- We import math to make basic operations
- We define the rectangle function that receives perimeter and area
- We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
- We calculate the second root of the quadratic equation for the same side (l1_2)
- We calculate the second side of the rectangle using the first root on w = a/h
- We calculate the second side of the rectangle using the second root on w= a/h
- We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
- If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
- if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found