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2 years ago

I don't understand proportional relationship can u help?

1 answer:

5 0

Answer: I’ll explain it in simpler terms for you. A proportional relationship is one in which two quantities vary directly with each other. Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional. An example of a proportional relationship is simple interest, tax, markups and markdowns, gratuities and commissions, fees, percent increase and decrease, percent error. Hope this helps! :D

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What is logs4 + logs3 written as a single logarithm? If possible, simplify the single logarithm.

stepan [7]

Answer:

I"m not sure if you wrote it the write way, but the answer is probably C

Step-by-step explanation:

log(a)+log(b)=log(ab)

This can be proven when you look at what a logarithm is.

8 0

2 years ago

Read 2 more answers

Question 7:

Mars2501 [29]

Answer:Graph A.

Step-by-step explanation:

Graph A.

Step-by-step explanation:

We will try to understand the graph plotted for the change in temperature for whole day.

In the morning, temperature starts out around 50°F. As the day goes on, the temperature rises first slowly- Slope of the first line will be less.

Then temperature rises more quickly - Slope of the second line will be more than first line.

It stays constant for an hour- third line will be parallel to the x-axis for one hour gap.

Then the temperature dropped down slowly - Last line of the graph will go down.

By the understanding we made for the graph we find graph A is the answer.

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2 years ago

Select a figure from the options which will replace the(?) as established by the problem figure

krok68 [10]

Answer:

a) is the correct answer.

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2 years ago

How to differentiate functions

Andreyy89

Answer: see boxed answers below

<u>Step-by-step explanation:</u>

(i) multiply the exponent to the coefficient then subtract 1 from the exponent.

$y=\dfrac{3}{5x^3}+3x^4+2x^2-20\\\\\\\text{rewrite it as follows}: y=\dfrac{3}{5}x^{-3}+3x^4+2x^2-20x^0\\\\\\y'=(-3)\dfrac{3}{5}x^{-3-1}+(4)3x^{4-1}+(2)2x^{2-1}-(0)20x^{0-1}\\\\\\y'=-\dfrac{9}{5}x^{-4}+12x^3+4x^1-0\\\\\\y'=\large\boxed{-\dfrac{9}{5x^{4}}+12x^3+4x}$

(ii) Use the division formula: $y = \dfrac{a}{b}\rightarrow \quad y'=\dfrac{ab'-a'b}{b^2}$

$a=5x^3+1\qquad \qquad a'=15x^2\\b=3x^5+4x^2\qquad \quad b'=15x^4+8x\\\\\\y'=\dfrac{(15x^2)(3x^5+4x^2)-(5x^3+1)(15x^4+8x)}{(3x^5+4x^2)^2}\\\\\\.\quad =\dfrac{45x^7+60x^4-75x^7-55x^4-8x}{(3x^5+4x^2)^2}\\\\\\.\quad =\large\boxed{\dfrac{-35x^7+5x^4-8x}{(3x^5+4x^2)^2}}$

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2 years ago

Will give brainlist plus will give brianlist plus 20 points

Andreas93 [3]

Answer: 8 60 70 i think if i am wrong pls let me know ty :D

Step-by-step explanation:

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1 year ago

I don't understand proportional relationship can u help? ​

I don't understand proportional relationship can u help?