Pretty sure the answer is 1.
Hope this helps.
(One point up from 1998, then 1 to the right gets you to 2000. 1/1 = 1)
Answer:
b)starts at zero at the beginning of the first period and then increases by a constant amount each period.
Step-by-step explanation:
A series is called arithmetic gradient series if it increases or decreases periodically by a constant amount.
Examples are
0,.100,200,300, 400 ....
Decreasing series would be
1000, 800, 600., 400....
Thus the difference between the consecutive terms is a constant.
Hence here out of four definitions we find that
b)starts at zero at the beginning of the first period and then increases by a constant amount each period.
Answer:
There could be many answers, please be more clearer.
Answer: .15
Step-by-step explanation:
The rule we'll use is
p^(q*r) = (p^q)^r
The exponents have been rearranged a bit.
In this case, p = 3.14, q = 159 and r = x, so,
p^(q*r) = (p^q)^r
3.14^(159*x) = (3.14^159)^x
This is in the form A^x with A = 3.14^159
