Answer:
It's the first option (A)
Step-by-step explanation:
Since it's heading towards negative Ys so in ax²+bx+c, a is negative and only option that a is negative in it, is option A.
Additionally, the parabola is moved 1 unit towards positive Xs, so —(x—1)²
and it's one unit up so —(x—1)²+1
It increases linearly, since it increases by about the same amount every month.
Answer:
Yes they are parellel
Step-by-step explanation:
Find the slope of both
5- -7 / 5 - 2 = slope of 4
1 - 5 / 4 - 5 = slope of 4
The answer you are looking for is (1, -8)
remember that: x=[(-b/2a)]
and that the problem is set up as y=ax^2+bx+c
calculate:
x=[-8/2(-4)]
x=[-8/-8]
x=1
then:
y=(-4)*1^2+(8*1)-12
y=(-4)+8-12
y=(-4)+8-12
y=4-12
y=(-8)
(1, -8)
Answer:
Proof:
By the inscribed angle theorem, we know that angle BAC is equal to angle DEC. By the second corollary to the inscribed angle theorem, we know that line segment AE is perpendicular to line segment AC. Therefore, line segment AE is tangent to circle C.
Step-by-step explanation:
Analyze and ensure the answer is correct.