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krek1111 [17]
4 years ago
13

Question 18: please help. I will give brainliest to correct answer.

Mathematics
2 answers:
Veronika [31]4 years ago
7 0

Answer:

3. mean of 2nd is larger

Step-by-step explanation:

mean of 2nd sem 87 > 86.8 1st sem

Nat2105 [25]4 years ago
6 0

Answer:

3

Step-by-step explanation:

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Carter can finish painting a fence in 10 hours. When Carter and Chase work together, they can finish painting the fence in about
belka [17]
You have to find the mean (average) which is (10+x)divided by 2 to get how long it would take them together. (chase is x because you don’t know how long yet so u use a variable)

6 0
3 years ago
1. Find the zeros of the function.
Mama L [17]
1. f(x) = 9x² + 6x - 8
f(x) = (3x - 2)(3x + 4)
When  (3x - 2) = 0, then x = 2/3
When (3x + 4) = 0, then x = -4/3

Answer: The zeros are two divided by three and negative four divided by three.

2. f(x) = 9x³ - 45x² + 36x
  f(x) = 9x(x² - 5x + 4)
        = 9x(x - 1)(x - 4)
  When 9x = 0, then x = 0
  When (x-1) = 0, then x = 1
  When (x-4) = 0, then x = 4

 Answer: 0, 1 and 4

3. f(x) = 4(x+7)²(x-7)³
 When (x+7)² = 0, then x = -7 (twice)
 When (x-7)³ = 0, then x = 7 (thrice)

 Answer: 7, multiplicity 2; -7 multiplicity 3

4. The zeros of f(x) are √5, -√5, -7
 The factors of f(x) are (x-√5)(x+√5)(x+7)
 Note that (x-√5)(x+√5) = x² - (√5)² = x² - 5
 f(x) = (x²-5)(x+7)
       = x³ + 7x² - 5x - 35

Answer: f(x) = x³ + 7x² - 5x - 35

5. Expand (2x + 4)³
 From Pascal's Triangle, the coefficients are 1 3 3 1
 Therefore
 (2x + 4)³ = 1(2x)³(4)⁰ + 3(2x)²(4)¹ + 3(2x)¹(4)² + 1(2x)⁰(4)³
                = 8x³ + 48x² + 96x + 64

 Answer: 8x³ + 48x² + 96x + 64
3 0
3 years ago
Chef Willie can make 54 pies in 2 hours. At this rate, how many pies can he make in 1 hour?
mihalych1998 [28]
27 pies in one hour 54=2 hours 54 divided by 2 equals 27
4 0
3 years ago
Hello can some one help with with a question?
marin [14]

Answer:

first you'I study and just a question from this app

3 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
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