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snow_tiger [21]

3 years ago

15

Una empresa comercial vende automóviles cuyo precio es de S/. 60 000, con una cuota inicial del 20%, para cancelar el saldo en 3

0 meses de plazo.calcula la cuota fija mensual que se pagará seda empresa cobra una tasa de interés simple del 12% semestralmente

1 answer:

Inessa05 [86]3 years ago

4 0

Responder:

2560

Explicación paso a paso:

Dado lo siguiente:

Precio del automóvil = 60000

Cuota inicial = 20% del precio = (0.2 * 60000 = 12,000

Saldo = (60000 - 12000) = 48000

La empresa cobra un interés simple del 12% cada 6 meses

Periodo de pago = 30 meses / 6 = 5 periodos

Interés simple: p * r * t

= 48000 * 0,12 * 5 = 28800

Por lo tanto, monto total a reembolsar, incluidos los intereses:

Balance + 28800; 48000 + 28800 = 76800

El reembolso mensual es fijo;

Por lo tanto,

76800/30 = 2560

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3 years ago

1200+0.075x>=3300 what is the solution to the inequality

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Solving inequalities is just like solving any other Algebraic problem...look to P.E.M.D.A.S. (Parenthesis, Exponents, Division, Addition, Subtraction). So lets take a look at this problem now.

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3 years ago

How to find the hypotenuse of a right angled triangle using trigonometry?

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3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Nimfa-mama [501]

Let's call our number <em>x</em>.

So we can setup the equation x² = 100.

To solve this equation, we square root both sides.

So we have x = ±10.

Always use plus or minus when square rooting both sides

of an equation so our answer is not only 10, it's also -10.

5 0

3 years ago

Read 2 more answers