Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
Answer:
180
Step-by-step explanation:
Answer:It would be 3/5 as well.
Step-by-step explanation:
Answer:
Sorry it's acually (h+3)(h-9)
Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;
- 1. Arcs are drawn to cross the given line twice on either side relative to the point
- 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line
Description:
1. One of the first steps is to place the compass on the point and from
point, draw arcs to intersect or cross the given line at two points.
2. The compass is placed at each of the intersection point in step 1 and
(opened a little wider when constructing from a point on the line) arcs are
drawn on one (the other side of the point off the line) side of the line with
the same opening (radius) of the compass to intersect each other.
3. From the point of intersection of the arcs in step 2, a line is drawn with a
straight edge passing through the given point.
Learn more about perpendicular lines here:
brainly.com/question/11505244
