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4 years ago

A scalene triangle can be equilateral. A. True B. False

2 answers:

6 0

No, It should be false. Because the scalene triangle it cannot be unequilateral.

Hope it helped you.

-Charlie

Have a great day!

:)

Andreyy894 years ago

4 0

False. Scalene triangle has no equal sides

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Write the equation of the quadratic function with roots 0 and 2 and a vertex at (1,5).

lisov135 [29]

Answer:

Step-by-step explanation:

y=a(x-0)(x-2)

=a(x^2-2x)

=a(x^2-2x+1-1)

or y=a(x-1)^2-a

(1,5) lies on it.

5=a(1-1)^2-a

5=0-a

or a=-5

so y=-5(x-1)^2+5

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3 years ago

Help me please... I have a lot more things to do and I wanna get this done.

lianna [129]

Answer:

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Step-by-step explanation:

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3 years ago

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A wise man once said "300 reduced by 3 times my age is 138"

Nonamiya [84]

The equation is 138=300-3x
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7 0

3 years ago

( 6 , -10 ) y (-15 , 15 ) <br><br><br> Finding slope from two points :)

svet-max [94.6K]

Answer:

-25/21

Step-by-step explanation:

m=(y2-y1)/(x2-x1)=(15-(-10))/(-15-6)=(15+10)/-21=25/-21

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3 years ago

Please help with #12 im confused<br> that is the key but i dont get it

Svetllana [295]

Given Equation

$\boxed{ \tt \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})}$

Step by step expansion:

$\dashrightarrow \sf \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})$

$\\ \\$

$\dashrightarrow \sf \: (8 \sqrt{3})^{2} - (2 \sqrt{2} {)}^{2}$

Reason:

(a + b)(a - b) = a²- b²

$\\ \\$

$\dashrightarrow \sf \: (8 {}^{2} \times { \sqrt{3} }^{2} )- (2 \sqrt{2} {)}^{2}$

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$\dashrightarrow \sf \: (64 \times 3 ) - (2 \sqrt{2} {)}^{2}$

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$\dashrightarrow \sf \: (64 \times 3 ) - (2 {}^{2} \times \sqrt{2} {}^{2} {)}$

$\\ \\$

$\dashrightarrow \sf \: 192- 8$

$\\ \\$

$\dashrightarrow \sf \: 184$

$\\ \\$

~BrainlyVIP ♡

4 0

2 years ago

Read 2 more answers