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BartSMP [9]
3 years ago
5

Write the equation of a line in slope intercept form if the slope of a line is -4 and the y intercept is -3

Mathematics
2 answers:
Anna007 [38]3 years ago
7 0
I believe that is it b.
Hope this helps.
Vanyuwa [196]3 years ago
5 0
The answer is B. If you need to explain it is because the equation is

y = slope(x) + y intercept

Therefor y=-4x+-3
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Pi divided by 2 is <span>1.57079632679 so anything bigger than 0 and less than that number should be between.</span>
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The volume of a sphere is 5,000 pie m^3. What is the surface area of the sphere to the nearest square meter?
ExtremeBDS [4]
The correct answer is A
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(y-x)(y+x) equals to<br>​
Len [333]
It equals y^2+yx-yx-x^2
6 0
2 years ago
The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in
Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

*<em> Lets explain how to solve the problem</em>

- Any point will be equidistant from the x-axis and the y-axis must have

 equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

 because the distance from the x-axis to the point is 4 (y-coordinate)

 and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

 (x_{1},y_{1})  and (x_{2},y_{2}), then

 x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

* <em>Lets solve the problem</em>

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ x=\frac{p+p+2q}{2}

∴ x=\frac{2p+2q}{2}

- Take 2 as a common factor from the terms of the numerator

∴ x=\frac{2(p+q)}{2}

- Divide up and down by 2

∴ x = p + q

∵ y=\frac{q+q+2p}{2}

∴ y=\frac{2q+2p}{2}

- Take 2 as a common factor from the terms of the numerator

∴ y=\frac{2(q+p)}{2}

- Divide up and down by 2

∴ y = q + p

∴ <em>The mid point of AB is (p + q , q + p)</em>

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

   x-axis and the y-axis

8 0
3 years ago
Find the product.<br><br> a^4(3a ^2 - 2a + 1)
Vikki [24]

<span>                   a⁴(3a² - 2a + 1)

We just have to multiply each term inside the parentheses by  a⁴  .

           a⁴</span><span>(3a²        )  =  3a⁶
 
           a⁴</span><span>(    - 2a    )  =  -2a⁵
 
           a⁴</span><span>(            1)  =  a⁴

Now, just addum up :      3a⁶ - 2a⁵ + a⁴</span>


7 0
3 years ago
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