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murzikaleks [220]

2 years ago

13

N

1 answer:

AlladinOne [14]2 years ago

7 0

What model?

I can’t see a problem

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Can someone help me pls? Thankss:)

zloy xaker [14]

Answer: C

Step-by-step explanation:

8 0

3 years ago

Given right triangle MNL what is the value of cos(M)?

FromTheMoon [43]

Step $1$

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

$ML^{2} =NL^{2} +MN^{2}$

Solve for MN

$MN^{2}=ML^{2} -NL^{2}$

in this problem

$ML=25\ units\\ NL=15\ units$

Substitute in the formula above

$MN^{2}=25^{2} -15^{2}$

$MN^{2}=400$

$MN=20\ units$

Step $2$

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

$cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}$

$adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units$

Substitute

$cos (M)=\frac{20}{25}$

$cos (M)=\frac{4}{5}$

$cos (M)=0.8$

therefore

The answer is

The value of cos(M) is equal to $0.8$

6 0

3 years ago

5<br> 8<br> y<br> Find the exact value of y.<br> y =

inn [45]

Answer:

$y=2\sqrt{10}$

Step-by-step explanation:

By applying geometric mean theorem in the given right angle,

$\frac{AD}{DB}=\frac{DB}{CD}$

By substituting values in the given ratio,

$\frac{5}{y}= \frac{y}{8}$

$y^2=8\times 5$

$y^2=40$

$y=2\sqrt{10}$

Exact value of y is $2\sqrt{10}$ .

8 0

3 years ago

Which numbers are perfect squares? Check all that apply.

Andrew [12]

A perfect square is a number made by squaring a whole number.

Since

$1^2=1;$
$4^2=16;$
$10^2=100,$

numbers 1, 16, 100 are perfect squares. You cannot find such whole number n, that

$2=n^2;$
$18=n^2;$
$32=n^2;$
$44=n^2;$
$94=n^2,$

therefore, numbers 2, 18, 32, 44, 94 are not perfect squares.

Answer: 1, 16, 100.

4 0

3 years ago

Read 2 more answers

What is x equal to????

Ksju [112]

Answer:

x = 20

Step-by-step explanation:

The 3 arcs UV, VW, WX form a semicircle, so sum to 180° , that is

4x + 2 + x + 78 = 180

5x + 80 = 180 ( subtract 80 from both sides )

5x = 100 ( divide both sides by 5 )

x = 20

5 0

3 years ago