Multitasking, it allows you to do more than one thing at once.
Answer:
#include <stdio.h>
int main()
{
float afTest1[5] = {90, 30, 25, 45, 55};
for (int i = 0; i < 5; i++) {
printf("%f ", afTest1[i]);
}
return 0;
}
Explanation:
Initialize the elements of the array as 90, 30, 25, 45, 55
Create a for loop that iterates through the array
Inside the loop, print each element using printf function
Only one daemon (server application) can bind to a port. The second one will fail.
Answer:
The pressure gauge reading will be;
12 psi
Explanation:
The question relates to relationship of pressure and area
The given parameters for the measurement are;
The weight of the load = 60 lb
The required area of the piston = 5 in.²
Pressure exerted by a force can be defined as follows;

The weight of the load = The force applied by the load
Therefore;

The gauge reading will be 12 psi.
The answer is: Lower overall taxes