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NeTakaya
3 years ago
11

PLEASE HELP!!!!! WILL MARK BEST ANSWER BRAINLIEST!!!~~~

Computers and Technology
2 answers:
maw [93]3 years ago
8 0

Answer:

D) PowerPoint has a free, built-in service for broadcasting online.

Explanation:

Sergeu [11.5K]3 years ago
5 0

Answer: D. PowerPoint has a free, built-in service for broadcasting online.

Explanation:

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The loop function is similar to range(), but handles the parameters somewhat differently: it takes in 3 parameters: the starting
nexus9112 [7]

Answer and Explanation:

def loop(start, stop, step):

   return_string = ""

   if step == 0:

       step = 1

   if start > stop:  # the bug was here, fixed it

       step = abs(step) * -1

   else:

       step = abs(step)

   for count in range(start, stop, step):

       return_string += str(count) + " "

   return return_string.strip()

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This is going to get taken down but I dont care add me on discord cause ima bored<br> -Red-#9847
Alex777 [14]

Answer:

I WILL

Explanation:

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Which of the following commands can be used to display socket information out to the terminal screen
Slav-nsk [51]
Linus ss

Explanation:

The ss (socket statistics) command provides a lot of information by displaying details on socket activity. One way to get started, although this may be a bit overwhelming, is to use the ss -h (help) command to get a listing of the command's numerous options. Another is to try some of the more useful commands and get an idea what each of them can tell you.

One very useful command is the ss -s command. This command will show you some overall stats by transport type. In this output, we see stats for RAW, UDP, TCP, INET and FRAG sockets.
6 0
2 years ago
NO SPAMMERS, ONLY FULL ANSWER
melisa1 [442]

Answer:

true

Explanation:

4 0
3 years ago
Read 2 more answers
In this lab, you use the flowchart and pseudocode found in the figures below to add code to a partially created C++ program. Whe
never [62]

Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   

   stringstream tream(Rank);

   tream>>classRank;

   

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

<em>    stringstream sstream(Score);</em>

<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

3 0
3 years ago
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