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Orlov [11]
3 years ago
7

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Check all that apply.

Mathematics
1 answer:
jonny [76]3 years ago
8 0
First, we find the slope of the given line.

<span>3x − 4y = 7

-4y = -3x + 7

y = (3/4)x - 7/4

The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.

Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),

We use the point-slope form of the equation of a line.

y - y1 = m(x - x1)

y - (-2) = (3/4)(x - (-4))

y + 2 = (3/4)(x + 4)     <---- check option E. Is the fraction 3/4 not there?

y + 2 = (3/4)x + 3

y = (3/4)x + 1

4y = 3x + 4

3x - 4y = -4    <------ this is choice B.
</span>
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Step-by-step explanation:


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Need help with this problem
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Okay we'll start easy
46*93
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So the missing numbers.

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3 years ago
5-2(4a+1)+3a=13 <br><br> A= 2/3<br> A= -2<br> A= -6/5<br> A=2
VMariaS [17]

Answer:

                   a = -2

Simplifying 5 + -2(4a + 1) + 3a = 13 Reorder the terms: 5 + -2(1 + 4a) + 3a = 13 5 + (1 * -2 + 4a * -2) + 3a = 13 5 + (-2 + -8a) + 3a = 13 Combine like terms: 5 + -2 = 3 3 + -8a + 3a = 13 Combine like terms: -8a + 3a = -5a 3 + -5a = 13 Solving 3 + -5a = 13 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5a = 13 + -3 Combine like terms: 3 + -3 = 0 0 + -5a = 13 + -3 -5a = 13 + -3 Combine like terms: 13 + -3 = 10 -5a = 10 Divide each side by '-5'. a = -2

6 0
3 years ago
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