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2 years ago

Can Someone Help me, pls?

Mathematics

2 answers:

vesna_86 [32]2 years ago

6 0

Answer:

6.25 <7

Step-by-step explanation:

aalyn [17]2 years ago

3 0

Answer:

(1) $x\leq 4$

(2) $x\geq 4$

Step-by-step explanation:

$\frac{1}{4}x + 6\leq 7\\(4) \frac{1}{4}x + 6\leq 7(4)\\x+24\leq 28\\ - 24 -24\\x\leq 4$ $-5x-24\leq -44\\+24 +24\\-5x\leq -20\\\frac{-5x\leq -20}{-5} \\x\geq 4$

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In their yard, Larry’s parents decided to plant tomatoes in a certain area. They chose an area that was of a yard long and of a

Marianna [84]

the answer is 18/18 which is the first one

3 0

2 years ago

C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature

Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$