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DerKrebs [107]
2 years ago
12

The sum of 2 nubers ,one of which is two third of the other,is 45.Find the smaller number​

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

Answer:

18

Step-by-step explanation:

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Which two numbers have a mean of 10 and a range of 4
Elden [556K]

Answer:

12 and 8

Step-by-step explanation:

set two numbers as x and y

mean of 10   →   x+y/2=10

range of 4    →   x-y=4

     x+y=20

+    x-y=4

____________

      2x=24, x=12  

      12-y=4, y=8        

6 0
3 years ago
Arithmetic sequence
KonstantinChe [14]

Answer: Arithmetic Sequence

Step-by-step explanation:

An Arithmetic Sequence is a sequence where each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.

5 0
2 years ago
How much sales tax would you pay on a dirt bike that cost $215 with a 5.3%<br> sales tax?
Archy [21]

Answer:

11.40

Step-by-step explanation:

215×0.053=11.395 rounded up to $11.40

7 0
3 years ago
12+4y^2-7<br><br><br> please help i will give brainliest
Dennis_Churaev [7]

Answer: 4 2^ + 5

Step-by-step explanation:

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8 0
2 years ago
Find cos(2*ABC) 100POINTS
juin [17]

Answer:

-\dfrac{7}{25}

Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

7 0
2 years ago
Read 2 more answers
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