2 years ago

The sum of 2 nubers ,one of which is two third of the other,is 45.Find the smaller number

1 answer:

8 0

Answer:

Step-by-step explanation:

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olchik [2.2K]

Answer:

8/-7

Step-by-step explanation:

using the equation: y₂-y₁/x₂-x₁

10-2/0-7 = 8/-7

3 0

3 years ago

IgorLugansk [536]

8 & 2

8+2 = 10

8-2 = 6

3 0

3 years ago

brilliants [131]

900 - 250 = 650

650 / 250 = 13 / 3 = 2.6 = 260%

5 0

3 years ago

allochka39001 [22]

Answer:

y= -1x+ 7

Step-by-step explanation:

x in a equation is slope and the other number is y- intercept

3 0

2 years ago

Aleksandr [31]

$Solution: \left(2x^2+4x-3\right)-\left(2x^2+4x-3\right)=0$

Steps:

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a, =2x^2+4x-3-\left(2x^2+4x-3\right)$

$-\left(2x^2+4x-3\right):\quad -2x^2-4x+3$

$=2x^2+4x-3-2x^2-4x+3$

$\mathrm{Simplify}\:2x^2+4x-3-2x^2-4x+3:\quad 0$

8 0

3 years ago

The sum of 2 nubers ,one of which is two third of the other,is 45.Find the smaller number​