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Vlada [557]
4 years ago
5

Please help. I don’t understand what to do

Mathematics
1 answer:
11111nata11111 [884]4 years ago
6 0

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=23.9\\ h=100 \end{cases}\implies V=\cfrac{\pi (23.9)^2(100)}{3} \\\\\\ V=\cfrac{57121\pi }{3}\implies V\approx 59816.97\implies \stackrel{\textit{rounded up}}{V=59817} \\\\[-0.35em] ~\dotfill

now, for the second one, we know the diameter is 10, thus its radius is half that or 5.

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5\\ V=225 \end{cases}\implies 225=\cfrac{\pi (5)^2 h}{3}\implies 225=\cfrac{25\pi h}{3} \\\\\\ \cfrac{225}{25\pi }=\cfrac{h}{3}\implies \cfrac{9}{\pi }=\cfrac{h}{3}\implies \cfrac{27}{\pi }=h\implies 8.59\approx h\implies \stackrel{\textit{rounded up}}{8.6=h}

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According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center (x_0,y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, we have that the center is at point (0,2), hence:

x^2 + (y - 2)^2 = r^2

It goes through point (3,3), hence:

3^2 + (3 - 2)^2 = r^2

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Hence, the equation is:

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<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))

Applying implicit differentiation, we have that:

2x + 2y\frac{dy}{dy} = 0

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Point W(3,3), hence:

(x_0, y_0) = (3,3)

\frac{dy}{dx} = -\frac{3}{3} = -1

Hence the equation is:

y - 3 = -(x - 3).

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More can be learned about the equation of a tangent line at brainly.com/question/8174665

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