Answer:
A = 25.758 m²
Step-by-step explanation:
Width of the sand pit, b = 2.7 m
Length of the sand pit, l = 9.54 m
We want to cover the sand pit with a piece of plastic. We need to find how many square meters of plastic will be needed to cover the sand pit. It is equal to the area of sand pit. It is in the shape of rectangle. Its area is given by :
A = l × b
A = 2.7 × 9.54
A = 25.758 m²
So, 25.758 m² of plastic will be needed to cover the sand pit.
Answer:
1 quick fix 2 solving 3 result
Step-by-step explanation:
hope it helps
Answer:
n=-2
Step-by-step explanation:
1−(2n+9)=4(1−2)
1+−1(2n+9)=4(1−2)
1+−1(2n)+(−1)(9)=4(1−2)
1+−2n+−9=4(1−2)
1+−2n+−9=−4
(−2n)+(1+−9)=−4
−2n+−8=−4
−2n−8=−4
−2n−8+8=−4+8
−2n=4
Divide both sides by -2
-2n/2=4/-2
n=-2
2 Simpify:
a -4 X x = -4x
b -10 X y = -10y
c -1 X a = -a
d b X (-1) = -b
e -4 X 2m = -8m
f 6 X -3a = -18a
g -8 X -3a = 24a
h -6m X 4 = -24m
i -7 X 8n = -56n
j -a X -3 = 3a
k 6x / -2 = -3x
l -10m / -5 = 2m
m -24a / 8 = -3a
n 2(m+3)-8=2(m)+2(3)-8=2m+6-8=2m-2
o 5(m-1)+9=5(m)+5(-1)+9=5m-5+9=5m+4
p 3(a-5)+10=3(a)+3(-5)+10=3a-15+10=3a-5
q 4(2x+1)-8x=4(2x)+4(1)-8x=8x+4-8x=4
r 3(10-2x)+3x=3(10)+3(-2x)+3x=30-6x+3x=30-3x
s 4(3-x)+9x=4(3)+4(-x)+9x=12-4x+9x=12+5x
3 Simplify by collecting like terms:
a 7a-5b+2a-6b=(7+2)a+(-5-6)b=(9)a+(-11)b=9a-11b
b 11x-2y-5x+7y=(11-5)x+(-2+7)y=(6)x+(5)y=6x+5y
c 3m+2g-5g-4m=(3-4)m+(2-5)g=(-1)m+(-3)g=-m-3g
d 6a-7-9a+10=(6-9)a+(-7+10)=(-3)a+(3)=-3a+3
e 7p-2q-6p+3q=(7-6)p+(-2+3)q=(1)p+(1)q=p+q
f 3x+7-12-5x=(3-5)x+(7-12)=(-2)x+(-5)=-2x-5
g 2ab+3bc-5ab+bc=(2-5)ab+(3+1)bc=(-3)ab+(4)bc=-3ab+4bc
h 6t^2+3t-5t^2-8t=(6-5)t^2+(3-8)t=(1)t^2+(-5)t=t^2-5t
i 9y-6z-9y+5z=(9-9)y+(-6+5)z=(0)y+(-1)z=0-z=-z
j 2k-3k^2-4k+k^2=(2-4)k+(-3+1)k^2=(-2)k+(-2)k^2=-2k-2k^2
k 10t+5w+t-7w=(10+1)t+(5-7)w=(11)t+(-2)w=11t-2w
l 7a-3b-8a-5b=(7-8)a+(-3-5)b=(-1)a+(-8)b=-a-8b
Answer:
7 to the second power... because 7 times is 49 and 49-49 is 0... so 7 to the second power
