100,000,000 X 100,000,000

$600 is deposited in an account that pays 7% annual interest, compounded continuously. What is the balance after 5 years? Please

CaHeK987 [17]

Answer:

$660

Step-by-step explanation:

P = $600

r =10%

n = 5 years

$Amount=P*(1+\frac{r}{100})^{n}\\\\=600*(1+\frac{10}{100})^{5}\\\\=600*(\frac{110}{100})^{5}\\\\=600*(1.1)^{5}\\\\=600*1.61051\\\\=660$

7 0

4 years ago

Office occupancy in a city is an indication of the economic health of the region in which it is located. A random sample of offi

Pani-rosa [81]

Answer:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

Step-by-step explanation:

$p_1$ represent the real population proportion for 1

$\hat p_1 =\frac{22}{165}=0.13$ represent the estimated proportion for 1

$n_1=165$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =\frac{14}{140}=0.10$ represent the estimated proportion for 2

$n_2=140$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For the 99% confidence interval the significance is $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , and the critical value using the normal standard distribution.

$z_{\alpha/2}=2.58$

Replacing we got:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

8 0

3 years ago

You and your friends have just measured the heights of your dogs. The heights are 600mm, 470mm, 170mm, 430mm and 300mm. Find out

Rufina [12.5K]

Answer:

To find the mean, you have to add all numbers together and divide them by the number of data points.

let me show what I mean:

The heights of the dogs are 600,470,170, 430,300.

Step-by-step explanation:

600+470+170+430+300.

1970.

Now we have to divide 1,970 by 5 ( because we are given 5 data points)

The mean is:

1970/5=394

Variance: First, arrange the data from least to greatest.

s2 = 27130

Standard Deviation: 164.71187

3 0

3 years ago

A car travels 32 km due north and

xenn [34]

Answer:

73.2km

Step-by-step explanation:

first you have to decompose 46 km into y and x components.

x=sin40°*46km

x=0.64*46km

x=29.44km

y=cos40°*46km

y=0.76*46km

y=34.96

now you add the y components together

32+34.96=66.98

finally use Pythagorean thereom to find the resultant vector.

a*a+ b*b=c*c

66.98*66.98+29.44*29.44=c*c

c*c= 4486.3+866.7

c=√5353

c=73.2 km this is the approximate value

6 0

3 years ago

Use the distrubitive property to multiply 5(b + 8)

Scorpion4ik [409]

Answer:

5b + 40.

Step-by-step explanation:

5 x B is 5b. 5 x 8 is 40. so final answer is 5b plus 40. Brainliest?

7 0

4 years ago

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