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satela [25.4K]
3 years ago
13

What is the equation of the line in slope-intercept form?

Mathematics
2 answers:
Vaselesa [24]3 years ago
4 0
I belive it would be y=-5/1x+6?

But im only like 90% sure so dont take my word for it but i hope that right?
ddd [48]3 years ago
4 0

Answer:

y=-5x+6

Step-by-step explanation:

To find your slope (or m value), you must identify 2 points that your line crosses through (I used (1,1) and (0,6). You can either count up and over to the point (0,6) from (1,1), or you can use the formula y2-y1/x2-x1 (it would look like 6-1/0-1). This will give you -5 for your slope.

Your x-intercept (or b value) is 6 because you can see from the graph that that is where your line intercepts y.

I hope this helped :)

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The amount of shaft wear after a fixed mileage was determined for each of seven randomly selected internal combustion engines, r
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t=\frac{0.0372-0.035}{\frac{0.0125}{\sqrt{7}}}=0.466  

p_v =P(t_{6}>0.466)=0.329  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 0.035 at 5% of significance.  

Step-by-step explanation:

We assume that the hypothesis that they want to check is :

Null hypothesis: \mu \leq 0.035

Alternative hypothesis: \mu >0.035

Data given and notation  

\bar X=0.0372 represent the sample mean  

s=0.0125 represent the sample standard deviation  

n=7 sample size  

\mu_o =0.035 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 0.035, the system of hypothesis are :  

Null hypothesis:\mu \leq 0.035  

Alternative hypothesis:\mu > 0.035  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{0.0372-0.035}{\frac{0.0125}{\sqrt{7}}}=0.466  

P-value  

We can find the degrees of freedom like this:

df = n-1 = 7-1 =6

Since is a one-side upper test the p value would given by:  

p_v =P(t_{6}>0.466)=0.329  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 0.035 at 5% of significance.  

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4 years ago
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