Check the picture below, on the left side.
since the triangle ABC is an isosceles with twin sides, if we drop a line bisecting the angle at the vertex A, we end up with a perpendicular line that cuts the "base" in two equal halves, so then
as you can see in the picture in red, now let's find CD.
The standard form for an equation is y=mx+b. You find the slope by using the formula of rise over run. This means that for problem 6 you first look to see if its positive or negative slope. The slope is positive if the line is going uphill and if its going downhill its negative. The slope would be negative for number 6 because it is going downhill. Then for the actualy slope you would start with rise. So you look at the point (0,1) and go up 3 until you hit the line of the other point and run over 2. So your slope would be -3/2.
Its the first one
Plugging in x = -2 and y = -1:-
5(-2) = -10
11(-2) - (9)-1) = -22 + 9 = -13
Answer:
Step-by-step explanation:
point (2,−8) and has a slope of 4.
y1 = -8 & x1 = 2 and m = 4
y - y1 = m(x - x1)
y - (-8) = 4(x - 2)
y + 8 = 4x - 8
y = 4x - 8 - 8
y = 4x -16
1) Given: f(x) = 3 - x; g(x) = -2x Find g[f(-1)].
g(f(x)) = -2(3 - x) = 2x - 6
g(f(-1)) = 2(-1) - 6 = -2 -6 = -8
g(f(-1)) = -8
Looks like the question 2 and 1 are the same
Both find g(f(-1))
