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Aleks [24]
3 years ago
6

The least common multiple of 9 and 42 through prime factorization?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

3

Step-by-step explanation:

9= 3*3

42=3*7*2

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Can someone please solve for x
RoseWind [281]

Answer:

x = -11

Step-by-step explanation:

2x + 23 + 9 = x + 21

Combine common factors

2x + 32 = x + 21

Subtract x from both sides

x + 32 = 21

Subtract 32 from both sides

x = -11

5 0
3 years ago
1. The hypotenuse of a right triangle measures 2 sqrt 15 centimeters and its shorter leg measures 2 sqrt 6
Dominik [7]

Answer:

<h2>50.8°</h2>

Step-by-step explanation:

First, we need to use the Pythagorean Theorem to find the third side. We will then use the law of cosines to find the angle.

2√15² = 2√6² + b²

60 = 24 + b²

Subtract 24

36 = b²

b = 6

Now, that we have all three sides, we will use the law of cosines to figure out the angle.

c² = a² + b² - 2abCosC°

Substitute the values in.

6² = 2√15² + 2√6² - 2(2√15)(2√6)CosC°

36 = 60 + 24 - 2(37.947331922)CosC°

36 = 60 + 24 - 75.894663844CosC°

36 = 84 - 75.894663844CosC°

Subtract 84

-48 = -75.9CosC°

0.63241106719 = CosC°

Arccos (0.63241106719) = 50.77176844°

The largest acute angle is approximately 50.8°

8 0
3 years ago
Read 2 more answers
In a state swim meet, none of the swimmers competing share a name. If the set of swimmers in the 100-m buterfly race is equal to
Dafna11 [192]

Answer:

The correct option is;

C. The only swimmers in the 100-m butterfly race are from the rival swim team

Step-by-step explanation:

The question is a word problem

The given information in the question are;

The names (first and last names) of all the competitors are different

The set, (which are the names) of the swimmers taking part in the 100-m butterfly race = The set (which contains the names) of swimmers from the rival team

Therefore, the only members of the set (the only names in the set) of swimmers taking part in the 100-m butterfly race are (the names of the swimmers from the rival swim team) from the rival swim team.

8 0
3 years ago
A book has 200 pages. The number of mistakes on each page is a Poisson random variable with mean 0.01, and is independent of the
aleksandr82 [10.1K]

Answer:

198 pages have no mistakes.                                      

Step-by-step explanation:

We are given the following in the question:

The number of mistakes on a page follows a poison distribution with

\mu = \lambda = 0.01

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

We have to find the probability that there are no mistakes on a page.

P(X =0) = \displaystyle\frac{(0.01)a^0 e^{-0.01}}{0!} = 0.9901

Thus, approximately 99.01% of the pages have no mistakes.

Number of pages =

\text{Total number of pages}\times 99.01\%\\\\200\times \dfrac{99.01}{100}\\\\\approx 198

Thus, 198 pages have no mistakes.

5 0
4 years ago
4/5 = 28/x <br><br> x= <br> i need to know what x =
ella [17]

Answer:

Hello! :) have a good day!

x = 35

4/5 = 28/35

5 0
3 years ago
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