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Bogdan [553]
3 years ago
7

HCF of algebraic expression x square minus y square and x y minus y square. ​

Mathematics
1 answer:
valina [46]3 years ago
6 0

Answer:

(x-y+z)(x-y-z)

Given (x²-2xy+y²) - z²

= (x-y)² - z²

/* By algebraic identity

a²-2ab+b² = (a-b)² */

=[(x-y)+z][(x-y)-z]

/* a²-b² = (a+b)(a-b) */

= (x-y+z)(x-y-z)

Therefore,

(x²-2xy+y²)-z² =(x-y+z)(x-y-z)

Step-by-step explanation:

x

2

y

2

=x×x×y×y

xy

2

=x×y×y

h.c.f=xy

2

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The owners of the pet sitting business have set aside $48 to purchase chewy toys for dogs, 2,
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<h3>Equation</h3>

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At Marco's market:

2x + 6y = 48 (1)

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Find out more on Equation at: brainly.com/question/13763238

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\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}

Given linear equⁿ : x - 2y = 6 .

So , on drawing its graph , the points though which it passes , the coordinates of that particular point will be a solution for this linear equⁿ .

Here , taking the given equⁿ & drawing its graph ,

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Now , for a given value of y , x will also have some values .

\boxed{\begin{tabular}{|c|c|c|}\cline{1-3} \bf x & 6 & 8 \\ \cline{1-3} \bf y & 0 & 1 \\\cline{1-3} \end{tabular}}

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[ Also Refer to graph in the attachment ]

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3 years ago
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