2/7 not sure but that's what i got
Answer:
9
Step-by-step explanation:
First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:
![x=\frac{13+-16+6}{3}=3/3=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B13%2B-16%2B6%7D%7B3%7D%3D3%2F3%3D1)
<em>y</em> is the cube root of 8. Thus:
![y=\sqrt[3]{8}=2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
So:
![x^2+y^3\\=(1)^2+(2)^3\\=1+8=9](https://tex.z-dn.net/?f=x%5E2%2By%5E3%5C%5C%3D%281%29%5E2%2B%282%29%5E3%5C%5C%3D1%2B8%3D9)
16-4=12
8x=12
÷8
x=12/8
x=3/2
x=1.5
Answer: 81/100
Step-by-step explanation:
I don't guarantee you I am right but..
first, solve for the exponents after substituting the numbers in
3/5 x 3/5 is 9/25
since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive
2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4
then you mutiply both numbers to get 9/4 x 9/25 is 81/100
Answer and Step-by-step explanation:
With the distributive property, the 8 will distribute itself to the a and the 4, resulting in <u>8a + 32</u>.
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