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3 years ago

Can someone please help me with math.

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

4- 20

I created an equation for this one:

4x+x=100

4x= four times the amount of the other number
x= the number
combine like terms

5x=100

divide by 5

x=20

5. One pretzel costs $3

Create an equation:

2s+p=7
4s+3p=17

Mulitply 2s+p=7 by -2 so you can use elimination.

-4s-2p=-14
4s+3p=17

Combine equations

p=3

Contact [7]3 years ago

7 0

For #3
there will be 8 geese and 12 pigs

the equation would be first to find out how many geese there are

pigs have 4 feet and geese have 2
g=geese p=pigs

4(20-g)+2g=8

now we know there are 8 geese which is 8•2 so 16 feet!

now use what we know to find out how many pigs there are

20-8 is 12 which means 12 pigs or 12•4 which means 48 feet

you can check it by adding the feet and animals

12+8=20 animals
48+16=64 feet!

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How many times doez 100,000,000 go into 1,000,000,000

Neko [114]

Answer:

100,000,000 goes 10 times into 1,000,000,000

5 0

4 years ago

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Erin is making a dozen cupcakes and wants to put 3 chocolate kisses on top of each one. How many does she need?

QveST [7]

Answer:

C. 36

Step-by-step explanation:

3x12=36 :]

3 0

3 years ago

Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.

Tanzania [10]

Answer:

z= 3.63

z for significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42 against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.

4 0

3 years ago

Of the people who fished at Clearwater Park today, 48 had a fishing license, 32and did not. Of the people who fished at Mountain

horrorfan [7]

Answer:

The probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.

Step-by-step explanation:

Denote the events as follows:

X = a fisher at Clearwater Park had a fishing license

Y = a fisher at Mountain View Park had a fishing license

The two events are independent.

The information provided is:

n (X) = 48

n (X') = 32

n (Y) = 72

n (Y') = 18

Then,

N (X) = n (X) + n (X')

= 48 + 32

= 80

N (Y) = n (Y) + n (Y')

= 72 + 18

= 90

Compute the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license as follows:

$P(X'\cap Y)=P(X')\times P(Y)$

$=\frac{n(X')}{N(X)}\times \frac{n(Y)}{N(Y)} \\\\=\frac{32}{80}\times\frac{72}{90}\\\\=0.32$

Thus, the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.

7 0

3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$