79.50 x .06 = 4.77
79.50 + 4.77 = $84.27
The total cost was $84.27
Answer:
list the integers within the interval
Step-by-step explanation:
Greater than or equal to 8, so 8 is part of this list.
Less than 16, so 16 is not in this list.
A) 264 11/2 *48
B) 66 pounds of beef needed .25*264
C) 66 pounds
"c" is the hypotenuse of the largest triangle, and "a" is that triangle's shortest side. Thus the ratio is
... (longest side)/(shortest side)
Since all the triangles in the figure are similar, to complete the proportion, you need to recognize the triangle that "a" is the longest side of, then find the shortest side of that triangle.
"a" is the longest side (hypotenuse) of the smallest triangle. The shortest side of that triangle is "r". So, your proportion is ...
... c/a = a/r
The appropriate choice is the 2nd one, ...
... r
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14
Formula
V = pi * r^2 * h
Calculations
r = d/2
r = 32/2
r = 16
V = 3.14 * 16^2 * 60
V = 48230 cubic yards [Cylinder's Volume]
Cone
<em>Formula</em>
V = 1/3 pi r^2 H
<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards
<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.
<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards
<em>Water Content</em>
The answer to this part requires a proportion.
1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x
1/201.97 = 53589 /x [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank.
10 819 092 gallons <<<< answer
B
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much.
Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius
New volume = 4 original volume. <<<<< answer to part B
