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Ivanshal [37]
3 years ago
13

PLS HURRY The number f of miles a ship is from its destination x hours after starting a voyage is given by f(x) = 120 - 30x. The

number f of miles a
submarine is from its destination x hours after leaving port is shown in the graph below. State the distance and length of time of each voyage.
Submarine Voyage

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

120 miles in 4.8 hours

75 miles in 5 hours

Step-by-step explanation:

Ship:

The number f(x) of miles a ship is from its destination x hours after starting a voyage is given by f(x) = 120 - 25x. This means, initially the ship is 120 miles away from its destination.

If the ship traveled 120 miles, then f(x)=0 (the ship will be 0 miles away from its destination) and

0 = 120 - 25x

25x = 120

x = 4.8 hours.

Submarine:

At x = 0 hours the submarine was 75 miles away

At x = 5 hours, the submarine was 0 miles away.

So, in 5 hours the submarine traveled 75 miles

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Answer:

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Step-by-step explanation:

The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;

R =(v^2 sin2θ)/g

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For the case above. When the projectile is launched at angle 13° above the horizontal.

θ1 = 13

R1 = (v^2 sin2θ1)/g

R1 = (v^2 sin26°)/g ....1

For the range to double

R2 = (v^2 sin2θ)/g .....2

R2 = 2R1

Substituting R2 and R1

(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g

Divide both sides by v^2/g

sin2θ = 2sin26

2θ = sininverse(2sin26)

θ = sininverse(2sin26)/2

θ = 30.63°

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Are you looking for

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