Answer:
s = 12cm
Step-by-step explanation:
Since these are similar triangles, in order to find a missing side, you have to find the constant of proportionality
14/8 = 21/s >> cross multiply
14s = 168 >> divide both sides by 14 to get s alone
s = 12
<em />
<em>another way to find the answer......</em>
Step-by-step explanation:
You still have to find the constant of proportionality, it's just going to be a bit faster this way
14/8 = 1.75
21/1.75 = 12
s = 12
i will bite - this is not a complete ans but an approximation:
there are 100*99*98 ways to pick 3 different no. out of 100
if 2 of the no. picked are >10, then there is no way the third no. can be larger than the products of the other 2 nos.
there are 90*89*98 ways to pick 2 nos between 10 and 100 and a third no. between 1 and 100.
So an approximate ans = 100*99*98 - 90*89*98 = 185220 but the actual ans will be smaller than this.
Answer: root18
Step-by-step explanation:
A (2,2) x1=2 y1=2
B (5,5) x2=5 y2=5
D(AB) = root [(x2-x1)^2 + (y2-y1)^2]
= root [(5-2)^2 + (5-2)^2]
= root [3^2 + 3^2]
= root (9+9)
D(AB)=root18
mark the brainliest plzz
Explanation:
a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.
__
b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.
__
c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.
_____
For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.
Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
___
<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
