Same=same figure out what the x is both x are the same number on both side is the same answer hope that helps
Answer:
Step-by-step explanation:
g(-7) = -7 + 2 = -5
Answer:
13.9
Step-by-step explanation:
Use Pythagorean Theorem:
Both of the lengths given are the legs,
13.5^2 + 3.2^2 = c^2
182.25 + 10.24 = c^2
192.49 = c^2
13.87 = c
Answer:
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Step-by-step explanation:
we know, ∠BGA = 90
In right angled triangle BGA
AB = 12 cm (diameter of circle)
⇒ (AB)2 = (AG)2 + (BG)2
⇒ 122 = 82 + (BG)2
⇒ BG = 4√5
In right angled triangle BCG
Let CG be x cm.
⇒ (BC)2 = (CG)2 + (BG)2
⇒ (BC)2 = x2 + (4√5)2 ----(1)
As we know,
⇒ (BC)2 = CG × CA ----(2)
From equation (1) and equation (2)
⇒ x2 + (4√5)2 = x × (x + 8)
⇒ x2 + (4√5)2 = x2 + 8x
⇒ 8x = 80
⇒ x = 10 cm
From equation (2)
⇒ (BC)2 = CG × CA
⇒ (BC)2 = 10 × 18 = 180
⇒ BC = √180 = 6√5
6 × 5 = 30
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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