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matrenka [14]
3 years ago
7

I will give brainlist,

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

f(8) = 38

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 5x - 2

f(8) is x = 8

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(8) = 5(8) - 2
  2. Multiply:                               f(8) = 40 - 2
  3. Subtract:                              f(8) = 38
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What is the rate of change of a line that passes through the points (-3,5) and (2,-1)?
lara [203]

Answer:

3/4

Step-by-step explanation:

The slope of the line is

m = (y2-y1)/(x2-x1)

   = (-2--5)/(6-2)

   = (-2+5)/(6-2)

    =3/4

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=p%5E%7B2%7Dxp%5E%7B2%7D" id="TexFormula1" title="p^{2}xp^{2}" alt="p^{2}xp^{2}" align="absmidd
vichka [17]

Answer:

{p}^{4} x

Step-by-step explanation:

1) Regroup terms.

{p}^{2} p^{2} x

2) Use product rule.

{p}^{2 + 2} x

3) Simplify 2 × 2 to 4.

p ^{4} x

Therefor, the answer is p⁴x

5 0
3 years ago
Read 2 more answers
Which of the following is a solution of x2 + 2x + 8?
GalinKa [24]
I hope this helps you


x^2+2x+8=0


x^2+2x+1+7=0


(x+1)^2= -7


(x+1)^2= i^2.7


x+1= i.square root of 7


x=-1+ i.square root of 7
5 0
4 years ago
The sign of the product of -35 and -625 is positive, negative, or zero
IRISSAK [1]

Answer:

Positive

Step-by-step explanation:

The product of two negative numbers has a positive sign, whereas the product of a positive and a negative number is negative.

Since -35 and -625 are both negative, they would have a positive sign for their product.

Hope this helps.

7 0
3 years ago
Evaluate: 5–^2 = <br> WILL MARK AS BRAINLIEST
Elanso [62]

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

For example:

x^{-2} or \frac{x^{-2}}{1}=\frac{1}{x^2}

\frac{1}{y^{-2}}=\frac{y^2}{1}  or  y²



So:

5^{-2}=\frac{1}{5^2}=\frac{1}{25}

Your answer is B

4 0
3 years ago
Read 2 more answers
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